# Nakafa Framework: LLM

URL: https://nakafa.com/en/exercises/high-school/snbt/quantitative-knowledge/try-out/set-5/13

Exercises: Try Out - Set 5: Real exam simulation to sharpen your skills and build confidence. - Problem 13

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## Exercise 13

### Question

export const metadata = {
  title: "Problem 13",
  authors: [{ name: "Nabil Akbarazzima Fatih" }],
  date: "12/23/2025",
};

The ratio of the length between the drawing and the original is as follows:
drawing size : original size = <InlineMath math="3 : 600" />.
If there is a rectangular field with an area of <InlineMath math="384\text{ m}^2" /> and a length of <InlineMath math="32\text{ m}" />, then the width of the field in the drawing is ... cm.


### Choices

- [ ] $$12$$
- [x] $$6$$
- [ ] $$5$$
- [ ] $$4$$
- [ ] $$3$$

### Answer & Explanation

export const metadata = {
  title: "Solution to Problem 13",
  authors: [{ name: "Nabil Akbarazzima Fatih" }],
  date: "12/23/2025",
};

First, we find the actual width of the field.
Given the area of the field <InlineMath math="L = 384\text{ m}^2" /> and length <InlineMath math="p = 32\text{ m}" />.
Then the actual width (<InlineMath math="l" />) is:
<MathContainer>
  <BlockMath math="l = \frac{L}{p}" />
  <BlockMath math="l = \frac{384}{32} = 12\text{ m}" />
</MathContainer>

Next, we convert the actual width to cm to match the drawing unit.
<MathContainer>
  <BlockMath math="12\text{ m} = 12 \times 100\text{ cm} = 1200\text{ cm}" />
</MathContainer>

Finally, we calculate the width of the field in the drawing using the scale ratio <InlineMath math="3 : 600" />.
<MathContainer>
  <BlockMath math="\text{Drawing width} = \frac{3}{600} \times \text{Actual width}" />
  <BlockMath math="\text{Drawing width} = \frac{3}{600} \times 1200" />
  <BlockMath math="\text{Drawing width} = \frac{1}{200} \times 1200" />
  <BlockMath math="\text{Drawing width} = 6\text{ cm}" />
</MathContainer>

So, the width of the field in the drawing is <InlineMath math="6\text{ cm}" />.


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