# Nakafa Framework: LLM

URL: https://nakafa.com/en/exercises/high-school/snbt/quantitative-knowledge/try-out/set-5/17

Exercises: Try Out - Set 5: Real exam simulation to sharpen your skills and build confidence. - Question 17

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## Exercise 17

### Question

export const metadata = {
  title: "Question 17",
  authors: [{ name: "Nabil Akbarazzima Fatih" }],
  date: "12/23/2025",
};

Andi's money is four times Budi's money. If Andi donates Rp4,000.00 and Budi spends Rp1,000.00, then the remainder of Andi's money is equal to the remainder of Budi's money plus Cici's money. If Cici's money <InlineMath math="= C" />, then Andi's initial money is


### Choices

- [ ] $$C + \text{Rp}4,000.00$$
- [ ] $$2C + \text{Rp}4,000.00$$
- [x] $$\frac{4}{3}C + \text{Rp}4,000.00$$
- [ ] $$\frac{3}{2}C + \text{Rp}1,000.00$$
- [ ] $$2C + \text{Rp}2,000.00$$

### Answer & Explanation

export const metadata = {
    title: "Answer to Question 17",
    authors: [{ name: "Nabil Akbarazzima Fatih" }],
    date: "12/23/2025",
};

Let Andi's initial money be <InlineMath math="A" />, Budi's money be <InlineMath math="B" />, and Cici's money be <InlineMath math="C" />.

Given that Andi's money is four times Budi's money, we can write the equation:

<MathContainer>
  <BlockMath math="A = 4B \implies B = \frac{1}{4}A" />
</MathContainer>

If Andi donates Rp4,000.00, his remaining money is <InlineMath math="A - 4,000" />.

If Budi spends Rp1,000.00, his remaining money is <InlineMath math="B - 1,000" />.

It is known that the remainder of Andi's money is equal to the remainder of Budi's money plus Cici's money. The equation is:

<MathContainer>
  <BlockMath math="A - 4,000 = (B - 1,000) + C" />
</MathContainer>

Next, substitute <InlineMath math="B = \frac{1}{4}A" /> into the equation to find the value of <InlineMath math="A" />:

<MathContainer>
  <BlockMath math="A - 4,000 = \left(\frac{1}{4}A - 1,000\right) + C" />
  <BlockMath math="A - \frac{1}{4}A = 4,000 - 1,000 + C" />
  <BlockMath math="\frac{3}{4}A = 3,000 + C" />
</MathContainer>

Multiply both sides by <InlineMath math="\frac{4}{3}" />:

<MathContainer>
  <BlockMath math="A = \frac{4}{3}(3,000 + C)" />
  <BlockMath math="A = 4,000 + \frac{4}{3}C" />
  <BlockMath math="A = \frac{4}{3}C + 4,000" />
</MathContainer>

So, Andi's initial money is <InlineMath math="\frac{4}{3}C + \text{Rp}4,000.00" />.


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