# Nakafa Framework: LLM URL: /en/subject/high-school/11/mathematics/polynomial/division-polynomial Source: https://raw.githubusercontent.com/nakafaai/nakafa.com/refs/heads/main/packages/contents/subject/high-school/11/mathematics/polynomial/division-polynomial/en.mdx Output docs content for large language models. --- export const metadata = { title: "Division of Polynomials", description: "Learn polynomial division algorithm with clear examples. Understand quotient, remainder concepts, and verify results using fractional & multiplication forms.", authors: [{ name: "Nabil Akbarazzima Fatih" }], date: "05/04/2025", subject: "Polynomial", }; ## Basic Concept of Polynomial Division Polynomial division is similar to the division of integers we are familiar with. When we divide one number by another, we get a quotient and a remainder. For example, when dividing 7 by 4: - can be written as (1 remainder 3) - This can also be written as Here: - 7 is the **dividend** - 4 is the **divisor** - 1 is the **quotient** - 3 is the **remainder** The same concept applies to polynomials. ## Polynomial Division Algorithm The division algorithm states the relationship between the dividend polynomial, the divisor, the quotient, and the remainder. If (the dividend) and (the divisor) are two polynomials, with , then there exist unique polynomials (the quotient) and (the remainder) such that: or it can be written as: with the condition that the degree of is less than the degree of , or (zero remainder). **Terminology:** - : Dividend Polynomial - : Divisor Polynomial - : Quotient Polynomial - : Remainder Polynomial **Illustrative Example:** The division of by yields: - Quotient - Remainder This can be written in two forms according to the algorithm: 1. Fractional form: 2. Multiplication form: Note that the degree of the remainder (, degree 0) is less than the degree of the divisor (, degree 1). ### Verifying the Division Algorithm We can prove the correctness of the second form above by multiplying the quotient by the divisor and then adding the remainder. Prove that . Let's expand the right side:
Since the right side equals the left side, the equation is proven true.