# Nakafa Framework: LLM

URL: /en/subject/high-school/12/mathematics/function-transformation/vertical-translation
Source: https://raw.githubusercontent.com/nakafaai/nakafa.com/refs/heads/main/packages/contents/subject/high-school/12/mathematics/function-transformation/vertical-translation/en.mdx

Output docs content for large language models.

---

export const metadata = {
  title: "Vertical Translation",
  description: "Unlock vertical translation secrets to move function graphs up and down effortlessly. See how adding constants shifts graphs while preserving their shape.",
  authors: [{ name: "Nabil Akbarazzima Fatih" }],
  date: "05/26/2025",
  subject: "Function Transformation",
};

import { getColor } from "@repo/design-system/lib/color";
import { LineEquation } from "@repo/design-system/components/contents/line-equation";

## Basic Concepts of Vertical Translation

Vertical translation is a geometric transformation that shifts the graph of a function up or down along the y-axis without changing the shape of the graph. Imagine lifting or lowering an object vertically, its shape remains the same, only its position changes.

If we have a function <InlineMath math="f(x)" />, then vertical translation produces a new function <InlineMath math="g(x) = f(x) + k" /> where <InlineMath math="k" /> is the translation constant.

### Rules of Vertical Translation

For any function <InlineMath math="f(x)" />, vertical translation is defined as:

<BlockMath math="g(x) = f(x) + k" />

Where:
- If <InlineMath math="k > 0" />, the graph shifts **upward** by <InlineMath math="k" /> units
- If <InlineMath math="k < 0" />, the graph shifts **downward** by <InlineMath math="|k|" /> units
- If <InlineMath math="k = 0" />, there is no translation (graph remains the same)

## Visualization of Vertical Translation

Let's see how vertical translation works on the linear function <InlineMath math="f(x) = 2x" />.

<LineEquation
  title={<>Vertical Translation of Linear Function <InlineMath math="f(x) = 2x" /></>}
  description="Notice how the graph shifts vertically without changing the slope of the line."
  showZAxis={false}
  data={[
    {
      points: Array.from({ length: 21 }, (_, i) => {
        const x = (i - 10) * 0.5;
        return { x, y: 2 * x, z: 0 };
      }),
      color: getColor("PURPLE"),
      labels: [{ text: "f(x) = 2x", offset: [1, 0.5, 0] }],
      showPoints: false,
    },
    {
      points: Array.from({ length: 21 }, (_, i) => {
        const x = (i - 10) * 0.5;
        return { x, y: 2 * x + 3, z: 0 };
      }),
      color: getColor("ORANGE"),
      labels: [{ text: "g(x) = 2x + 3", offset: [1, 0.5, 0] }],
      showPoints: false,
    },
    {
      points: Array.from({ length: 21 }, (_, i) => {
        const x = (i - 10) * 0.5;
        return { x, y: 2 * x - 2, z: 0 };
      }),
      color: getColor("TEAL"),
      labels: [{ text: "h(x) = 2x + (-2)", offset: [1, 0.5, 0] }],
      showPoints: false,
    },
  ]}
/>

From the visualization above, we can observe:
- The original function <InlineMath math="f(x) = 2x" /> passes through the origin
- Function <InlineMath math="g(x) = 2x + 3" /> is the result of translation upward by 3 units
- Function <InlineMath math="h(x) = 2x + (-2)" /> is the result of translation downward by 2 units

## Vertical Translation on Quadratic Functions

Now let's apply the same concept to the quadratic function <InlineMath math="f(x) = x^2" />.

<LineEquation
  title={<>Vertical Translation of Quadratic Function <InlineMath math="f(x) = x^2" /></>}
  description="The parabola shape remains the same, only its vertical position changes."
  showZAxis={false}
  data={[
    {
      points: Array.from({ length: 41 }, (_, i) => {
        const x = (i - 20) * 0.25;
        return { x, y: x * x, z: 0 };
      }),
      color: getColor("VIOLET"),
      labels: [{ text: "f(x) = x²", offset: [1, 1, 0] }],
      showPoints: false,
    },
    {
      points: Array.from({ length: 41 }, (_, i) => {
        const x = (i - 20) * 0.25;
        return { x, y: x * x + 4, z: 0 };
      }),
      color: getColor("AMBER"),
      labels: [{ text: "g(x) = x² + 4", offset: [1, 1, 0] }],
      showPoints: false,
    },
    {
      points: Array.from({ length: 41 }, (_, i) => {
        const x = (i - 20) * 0.25;
        return { x, y: x * x - 3, z: 0 };
      }),
      color: getColor("CYAN"),
      labels: [{ text: "h(x) = x² + (-3)", offset: [1, 1, 0] }],
      showPoints: false,
    },
  ]}
/>

Notice that:
- The vertex of the original parabola <InlineMath math="f(x) = x^2" /> is at <InlineMath math="(0, 0)" />
- After vertical translation +4, the vertex of <InlineMath math="g(x) = x^2 + 4" /> is at <InlineMath math="(0, 4)" />
- After vertical translation +(-3), the vertex of <InlineMath math="h(x) = x^2 + (-3)" /> is at <InlineMath math="(0, -3)" />

## Important Properties of Vertical Translation

### Graph Shape Remains Unchanged

Vertical translation preserves the original shape of the graph. The distance between points on the graph remains the same, only the vertical position changes.

### Effect on Coordinate Points

If point <InlineMath math="(a, b)" /> is on the graph of <InlineMath math="f(x)" />, then after vertical translation by <InlineMath math="k" />, that point becomes <InlineMath math="(a, b + k)" /> on the graph of <InlineMath math="f(x) + k" />.

### Domain and Range

- **Domain**: Does not change after vertical translation
- **Range**: Shifts by <InlineMath math="k" /> units

If the range of the original function is <InlineMath math="[c, d]" />, then the range after vertical translation <InlineMath math="k" /> becomes <InlineMath math="[c + k, d + k]" />.

## Application Examples

### Exponential Function Example

Let's look at vertical translation on the exponential function <InlineMath math="f(x) = 2^x" />.

<LineEquation
  title={<>Vertical Translation of Exponential Function <InlineMath math="f(x) = 2^x" /></>}
  description="The exponential curve maintains its characteristics after vertical translation."
  showZAxis={false}
  data={[
    {
      points: Array.from({ length: 31 }, (_, i) => {
        const x = (i - 15) * 0.2;
        return { x, y: Math.pow(2, x), z: 0 };
      }),
      color: getColor("INDIGO"),
      labels: [{ text: "f(x) = 2^x", offset: [0.5, 1, 0] }],
      showPoints: false,
    },
    {
      points: Array.from({ length: 31 }, (_, i) => {
        const x = (i - 15) * 0.2;
        return { x, y: Math.pow(2, x) + 2, z: 0 };
      }),
      color: getColor("EMERALD"),
      labels: [{ text: "g(x) = 2^x + 2", offset: [0.5, 1, 0] }],
      showPoints: false,
    },
    {
      points: Array.from({ length: 31 }, (_, i) => {
        const x = (i - 15) * 0.2;
        return { x, y: Math.pow(2, x) - 1, z: 0 };
      }),
      color: getColor("ROSE"),
      labels: [{ text: "h(x) = 2^x + (-1)", offset: [0.5, 1, 0] }],
      showPoints: false,
    },
  ]}
/>

For exponential functions:
- The horizontal asymptote <InlineMath math="y = 0" /> on <InlineMath math="f(x) = 2^x" /> shifts to <InlineMath math="y = k" /> on <InlineMath math="f(x) + k" />
- The y-intercept shifts from <InlineMath math="(0, 1)" /> to <InlineMath math="(0, 1 + k)" />

## Exercises

1. Given the function <InlineMath math="f(x) = x^2 + 4x + 3" />. Determine the equation of the function resulting from vertical translation upward by 5 units.

2. If the graph of function <InlineMath math="g(x) = 3x + 2" /> is translated vertically downward by 7 units, determine:
   - The equation of the resulting translated function
   - The y-intercept after translation

3. Function <InlineMath math="h(x) = \sqrt{x}" /> undergoes vertical translation such that point <InlineMath math="(4, 2)" /> becomes <InlineMath math="(4, 5)" />. Determine the translation constant value and the equation of the resulting translated function.

### Answer Key

1. Vertical translation upward by 5 units: <InlineMath math="f'(x) = f(x) + 5 = x^2 + 4x + 3 + 5 = x^2 + 4x + 8" />

   <LineEquation
     title={<>Function <InlineMath math="f(x) = x^2 + 4x + 3" /> and Its Translation Result</>}
     description="Original quadratic function and the result of vertical translation upward by 5 units."
     showZAxis={false}
     data={[
       {
         points: Array.from({ length: 41 }, (_, i) => {
           const x = (i - 20) * 0.25;
           return { x, y: x * x + 4 * x + 3, z: 0 };
         }),
         color: getColor("PURPLE"),
         labels: [{ text: "f(x) = x² + 4x + 3", at: 10, offset: [0, 1.5, 0] }],
         showPoints: false,
       },
       {
         points: Array.from({ length: 41 }, (_, i) => {
           const x = (i - 20) * 0.25;
           return { x, y: x * x + 4 * x + 3 + 5, z: 0 };
         }),
         color: getColor("ORANGE"),
         labels: [{ text: "f'(x) = x² + 4x + 8", at: 10, offset: [0, -0.5, 0] }],
         showPoints: false,
       },
     ]}
   />

2. Equation of the resulting translated function:
    
   - Translation downward by 7 units: <InlineMath math="g'(x) = g(x) + (-7) = 3x + 2 + (-7) = 3x + (-5)" />
   - Y-intercept: substitute <InlineMath math="x = 0" /> into <InlineMath math="g'(x) = 3(0) + (-5) = -5" />, so the intercept point is <InlineMath math="(0, -5)" />

   Visualization:

   <LineEquation
     title={<>Function <InlineMath math="g(x) = 3x + 2" /> and Its Translation Result</>}
     description="Original linear function and the result of vertical translation downward by 7 units."
     showZAxis={false}
     data={[
       {
         points: Array.from({ length: 21 }, (_, i) => {
           const x = (i - 10) * 0.5;
           return { x, y: 3 * x + 2, z: 0 };
         }),
         color: getColor("VIOLET"),
         labels: [{ text: "g(x) = 3x + 2", offset: [1, 0.5, 0] }],
         showPoints: false,
       },
       {
         points: Array.from({ length: 21 }, (_, i) => {
           const x = (i - 10) * 0.5;
           return { x, y: 3 * x + 2 - 7, z: 0 };
         }),
         color: getColor("TEAL"),
         labels: [{ text: "g'(x) = 3x + (-5)", offset: [1, 0.5, 0] }],
         showPoints: false,
       },
     ]}
   />

3. Point <InlineMath math="(4, 2)" /> on <InlineMath math="h(x) = \sqrt{x}" /> becomes <InlineMath math="(4, 5)" />, meaning vertical translation by <InlineMath math="k = 5 - 2 = 3" /> units upward.
   Equation of the translation result: <InlineMath math="h'(x) = \sqrt{x} + 3" />

   <LineEquation
     title={<>Function <InlineMath math="h(x) = \sqrt{x}" /> and Its Translation Result</>}
     description="Original square root function and the result of vertical translation upward by 3 units."
     showZAxis={false}
     data={[
       {
         points: Array.from({ length: 21 }, (_, i) => {
           const x = i * 0.25;
           return { x, y: Math.sqrt(x), z: 0 };
         }),
         color: getColor("INDIGO"),
         labels: [{ text: "h(x) = √x", offset: [1, 1, 0] }],
         showPoints: false,
       },
       {
         points: Array.from({ length: 21 }, (_, i) => {
           const x = i * 0.25;
           return { x, y: Math.sqrt(x) + 3, z: 0 };
         }),
         color: getColor("EMERALD"),
         labels: [{ text: "h'(x) = √x + 3", offset: [1, 1, 0] }],
         showPoints: false,
       },
     ]}
   />