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Learn how to identify significant figures, round measurement results, and report calculated values with the right precision.

---

## A Calculator Does Not Know the Tool Precision

When a bottle cap diameter is read as $$3.12 \text{ cm}$$, a calculator can produce many digits after the area is calculated. The measuring tool does not justify all of those digits. This is why we use **significant figures**.

Visible text: When a bottle cap diameter is read as , a calculator can produce many digits after the area is calculated. The measuring tool does not justify all of those digits. This is why we use **significant figures**.

Significant figures are the trusted digits in a measurement. The last digit is usually an estimated digit, meaning it is still reasonable based on the measuring tool.

```math
\text{measurement result}=\text{certain digits}+\text{last estimated digit}
```

The rule is not about making numbers shorter. It keeps a report from looking more precise than the measurement tool.

| Situation | Question to answer |
| :-------- | :----------------- |
| Reading one measurement | Which digits are actually supported by the tool? |
| Addition and subtraction | Which data has the smallest number of decimal places? |
| Multiplication and division | Which data has the smallest number of significant figures? |

## Zero Can Be a Digit or Hold Place Value

Zeros are tricky because their meaning depends on where they are written.

| Measurement writing | How to read the significant figures |
| :------------------ | :---------------------------------- |
| $$3.25 \text{ cm}$$ | Every nonzero digit counts, so there are $$3$$ significant figures. |
| $$1.004 \text{ cm}$$ | Zeros between nonzero digits count, so there are $$4$$ significant figures. |
| $$31.00 \text{ cm}$$ | Zeros after the decimal point count, so there are $$4$$ significant figures. |
| $$0.0026 \text{ kg}$$ | Zeros before the first nonzero digit only hold place value, so there are $$2$$ significant figures. |
| $$1000 \text{ m}$$ | Without a decimal point or another marker, trailing zeros are usually not treated as significant. |
| $$3.14 \times 10^{-5} \text{ m}$$ | The coefficient $$3.14$$ has $$3$$ significant figures |

Visible text: | Measurement writing | How to read the significant figures |
| :------------------ | :---------------------------------- |
| | Every nonzero digit counts, so there are significant figures. |
| | Zeros between nonzero digits count, so there are significant figures. |
| | Zeros after the decimal point count, so there are significant figures. |
| | Zeros before the first nonzero digit only hold place value, so there are significant figures. |
| | Without a decimal point or another marker, trailing zeros are usually not treated as significant. |
| | The coefficient has significant figures |

In scientific notation, a power such as $$10^{-5}$$ only gives the scale, not a new significant figure.

Visible text: In scientific notation, a power such as only gives the scale, not a new significant figure.

If a zero must be significant, write it in a way that removes ambiguity. Scientific notation is often the cleanest choice.

```math
\begin{aligned}
1000 \text{ m} \text{ with } 1 \text{ significant figure} &= 1 \times 10^3 \text{ m} \\
1000 \text{ m} \text{ with } 4 \text{ significant figures} &= 1.000 \times 10^3 \text{ m}
\end{aligned}
```

## Rounding Follows the Next Digit

After the allowed number of digits is known, inspect the first digit that will be dropped.

| First dropped digit | Decision |
| :------------------ | :------- |
| $$\ge 5$$ | Increase the last kept digit. |
| $$<5$$ | Keep the last kept digit unchanged. |

Visible text: | First dropped digit | Decision |
| :------------------ | :------- |
| | Increase the last kept digit. |
| | Keep the last kept digit unchanged. |

For example, if a calculated area is $$52.976686625 \text{ cm}^2$$ and it must be written to $$4$$ significant figures, the next digit is $$6$$.

Visible text: For example, if a calculated area is and it must be written to significant figures, the next digit is .

```math
52.976686625 \text{ cm}^2 \to 52.98 \text{ cm}^2
```

If the calculated value is $$52.973376625 \text{ cm}^2$$, the next digit is $$3$$.

Visible text: If the calculated value is , the next digit is .

```math
52.973376625 \text{ cm}^2 \to 52.97 \text{ cm}^2
```

## Addition Follows Decimal Position

For addition and subtraction, precision is judged by decimal position. The roughest data decides the final decimal place.

Suppose an iron rod of length $$8.235 \text{ cm}$$ is joined to another rod of length $$4.5 \text{ cm}$$.

Visible text: Suppose an iron rod of length is joined to another rod of length .

```math
\begin{aligned}
8.235 \text{ cm}+4.5 \text{ cm} &= 12.735 \text{ cm} \\
&\to 12.7 \text{ cm}
\end{aligned}
```

The value $$12.735 \text{ cm}$$ is rounded to $$1$$ decimal place because $$4.5 \text{ cm}$$ has only $$1$$ digit after the decimal point.

Visible text: The value is rounded to decimal place because has only digit after the decimal point.

## Multiplication Follows the Least Precise Data

For multiplication and division, the limiting value is the smallest number of significant figures among the measured data.

Suppose a rectangle has width $$12.455 \text{ cm}$$ and length $$35.2 \text{ cm}$$.

Visible text: Suppose a rectangle has width and length .

```math
\begin{aligned}
A &= l \times w \\
&= 35.2 \text{ cm} \times 12.455 \text{ cm} \\
&= 438.416 \text{ cm}^2 \\
&\to 438 \text{ cm}^2
\end{aligned}
```

The value $$12.455 \text{ cm}$$ has $$5$$ significant figures, while $$35.2 \text{ cm}$$ has $$3$$ significant figures. Therefore, the area is reported with $$3$$ significant figures.

Visible text: The value has significant figures, while has significant figures. Therefore, the area is reported with significant figures.

For a bottle cap with diameter $$3.12 \text{ cm}$$, constants such as $$\pi$$ and $$\frac{1}{4}$$ do not limit significant figures because they come from the formula, not from a measuring tool. In this example calculation, $$\pi$$ is approximated as $$3.14$$.

Visible text: For a bottle cap with diameter , constants such as and do not limit significant figures because they come from the formula, not from a measuring tool. In this example calculation, is approximated as .

```math
\begin{aligned}
A &= \frac{1}{4}\pi d^2 \\
&= \frac{1}{4}(3.14)(3.12 \text{ cm})^2 \\
&= 7.641504 \text{ cm}^2 \\
&\to 7.64 \text{ cm}^2
\end{aligned}
```

If the International System of Units (SI) is required, convert $$\text{cm}^2$$ to $$\text{m}^2$$. SI is the international standard for measurement units used in science.

Visible text: If the International System of Units (SI) is required, convert to . SI is the international standard for measurement units used in science.

```math
7.64 \text{ cm}^2 = 0.000764 \text{ m}^2 = 7.64 \times 10^{-4} \text{ m}^2
```

Rule references from OpenStax University Physics and NIST Technical Note $$1297$$ can be opened through [the OpenStax link](https://openstax.org/books/university-physics-volume-1/pages/1-6-significant-figures) and [the NIST link](https://www.nist.gov/pml/nist-technical-note-1297/nist-tn-1297-7-reporting-uncertainty).

Visible text: Rule references from OpenStax University Physics and NIST Technical Note can be opened through [the OpenStax link](https://openstax.org/books/university-physics-volume-1/pages/1-6-significant-figures) and [the NIST link](https://www.nist.gov/pml/nist-technical-note-1297/nist-tn-1297-7-reporting-uncertainty).