0000:00:00:00:00Start19Number 19ExplanationGiven f(x)=2x−3f(x) = 2x - 3f(x)=2x−3, g(x)=x2+4x−1g(x) = x^2 + 4x - 1g(x)=x2+4x−1, and (g∘f)(x)=ax2+bx+c(g \circ f)(x) = ax^2 + bx + c(g∘f)(x)=ax2+bx+c, then the value of a+b+c=a + b + c =a+b+c=444333000−3-3−3−4-4−4
19Number 19ExplanationGiven f(x)=2x−3f(x) = 2x - 3f(x)=2x−3, g(x)=x2+4x−1g(x) = x^2 + 4x - 1g(x)=x2+4x−1, and (g∘f)(x)=ax2+bx+c(g \circ f)(x) = ax^2 + bx + c(g∘f)(x)=ax2+bx+c, then the value of a+b+c=a + b + c =a+b+c=444333000−3-3−3−4-4−4
