0000:00:00:00:00Start9Number 9ExplanationFor the function f(x)=5−xx2+x−6f(x) = \frac{\sqrt{5 - x}}{\sqrt{x^2 + x - 6}}f(x)=x2+x−65−x to be defined in its domain, the domain of function fff is...Df={x∣x≤5}Df = \{x | x \leq 5\}Df={x∣x≤5}Df={x∣2<x≤5}Df = \{x | 2 < x \leq 5\}Df={x∣2<x≤5}Df={x∣x<−3 or 2<x<5}Df = \{x | x < -3 \text{ or } 2 < x < 5\}Df={x∣x<−3 or 2<x<5}Df={x∣x<−3 or 2<x≤5}Df = \{x | x < -3 \text{ or } 2 < x \leq 5\}Df={x∣x<−3 or 2<x≤5}Df={x∣x<−3 or 2≤x≤5}Df = \{x | x < -3 \text{ or } 2 \leq x \leq 5\}Df={x∣x<−3 or 2≤x≤5}
9Number 9ExplanationFor the function f(x)=5−xx2+x−6f(x) = \frac{\sqrt{5 - x}}{\sqrt{x^2 + x - 6}}f(x)=x2+x−65−x to be defined in its domain, the domain of function fff is...Df={x∣x≤5}Df = \{x | x \leq 5\}Df={x∣x≤5}Df={x∣2<x≤5}Df = \{x | 2 < x \leq 5\}Df={x∣2<x≤5}Df={x∣x<−3 or 2<x<5}Df = \{x | x < -3 \text{ or } 2 < x < 5\}Df={x∣x<−3 or 2<x<5}Df={x∣x<−3 or 2<x≤5}Df = \{x | x < -3 \text{ or } 2 < x \leq 5\}Df={x∣x<−3 or 2<x≤5}Df={x∣x<−3 or 2≤x≤5}Df = \{x | x < -3 \text{ or } 2 \leq x \leq 5\}Df={x∣x<−3 or 2≤x≤5}
