0000:00:00:00:00Start12Number 12ExplanationGiven that (x−1)(x - 1)(x−1) and (x+3)(x + 3)(x+3) are factors of the polynomial equation x3−ax2−bx+12=0x^3 - ax^2 - bx + 12 = 0x3−ax2−bx+12=0 If x1,x2,x_1, x_2,x1,x2, and x3x_3x3 are the roots of the equation and x1<x2<x3x_1 < x_2 < x_3x1<x2<x3, the value of x1+x2+x3x_1 + x_2 + x_3x1+x2+x3 is ....−5-5−5−3-3−3222333555
12Number 12ExplanationGiven that (x−1)(x - 1)(x−1) and (x+3)(x + 3)(x+3) are factors of the polynomial equation x3−ax2−bx+12=0x^3 - ax^2 - bx + 12 = 0x3−ax2−bx+12=0 If x1,x2,x_1, x_2,x1,x2, and x3x_3x3 are the roots of the equation and x1<x2<x3x_1 < x_2 < x_3x1<x2<x3, the value of x1+x2+x3x_1 + x_2 + x_3x1+x2+x3 is ....−5-5−5−3-3−3222333555