0000:00:00:00:00Start3Number 3ExplanationThe equation of the tangent line to the parabola y=x+1y = \sqrt{x} + 1y=x+1 passing through the point (−8,0)(-8, 0)(−8,0) is....4y−x−8=04y - x - 8 = 04y−x−8=04y+x−8=04y + x - 8 = 04y+x−8=04y+3x−2=04y + 3x - 2 = 04y+3x−2=04y−x+2=04y - x + 2 = 04y−x+2=04y−3x−2=04y - 3x - 2 = 04y−3x−2=0
3Number 3ExplanationThe equation of the tangent line to the parabola y=x+1y = \sqrt{x} + 1y=x+1 passing through the point (−8,0)(-8, 0)(−8,0) is....4y−x−8=04y - x - 8 = 04y−x−8=04y+x−8=04y + x - 8 = 04y+x−8=04y+3x−2=04y + 3x - 2 = 04y+3x−2=04y−x+2=04y - x + 2 = 04y−x+2=04y−3x−2=04y - 3x - 2 = 04y−3x−2=0