Question 30/40: Set 3 - Try Out 2026 - Mathematics (TKA) | Nakafa

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Question 30

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Number 30

Both roots of the quadratic equation $(m + 2)x^2 - (2m - 1)x + m + 1 = 0$ are negative. The range of values of $m$ that satisfies this is....

$m < -2 \text{ or } m > -1$

$-2 < m < -1$

$-2 < m < -\frac{1}{2}$

$-2 < m \leq -\frac{7}{16}$

$-1 < m \leq -\frac{7}{16}$

Number 29

Number 31

Question 30Set 3

Exercises

Number 30

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