For AI agents: use /llms.txt for the Nakafa content index.
The argument θ \theta θ of a complex number z = x + i y z = x + iy z = x + i y is the angle formed by the vector z z z with the positive real axis.
However, there's an important point: the argument is not a single value!
If θ \theta θ is an argument of z z z , then θ + 2 π k \theta + 2\pi k θ + 2 π k (where k k k is an integer: 0 , ± 1 , ± 2 , … 0, \pm 1, \pm 2, \ldots 0 , ± 1 , ± 2 , … ) is also an argument of z z z , because adding multiples of 360 ∘ 360^\circ 36 0 ∘ or 2 π 2\pi 2 π radians results in the same angle on the complex plane.
The angles 45 ∘ 45^\circ 4 5 ∘ , 405 ∘ 405^\circ 40 5 ∘ (45 ∘ + 360 ∘ 45^\circ + 360^\circ 4 5 ∘ + 36 0 ∘ ), and − 315 ∘ -315^\circ − 31 5 ∘ (45 ∘ − 360 ∘ 45^\circ - 360^\circ 4 5 ∘ − 36 0 ∘ ) all indicate the same direction.
Because there are infinitely many arguments for a single complex number, we often need a unique standard value. This value is called the Principal Argument .
The Principal Argument of a complex number z = r ( cos θ + i sin θ ) z = r(\cos \theta + i\sin \theta) z = r ( cos θ + i sin θ ) is the unique value of the argument θ \theta θ that satisfies a specific range.
Principal Argument (denoted Arg ( z ) \text{Arg}(z) Arg ( z ) ) is defined as the argument θ \theta θ that satisfies:
Note: Other definitions sometimes use the range ( − π , π ] (-\pi, \pi] ( − π , π ] or ( − 180 ∘ , 180 ∘ ] (-180^\circ, 180^\circ] ( − 18 0 ∘ , 18 0 ∘ ] . It's important to always check the definition being used in a specific context.
Determining the Principal Argument is the same as finding the regular argument, but we need to ensure the final result is within the range [ 0 , 2 π ) [0, 2\pi) [ 0 , 2 π ) or [ 0 ∘ , 360 ∘ ) [0^\circ, 360^\circ) [ 0 ∘ , 36 0 ∘ ) .
Find the Principal Argument of z = 1 + i z = 1 + i z = 1 + i
The point ( 1 , 1 ) (1, 1) ( 1 , 1 ) is in Quadrant I I I .
Since 45 ∘ 45^\circ 4 5 ∘ is already within the range [ 0 ∘ , 360 ∘ ) [0^\circ, 360^\circ) [ 0 ∘ , 36 0 ∘ ) , the Principal Argument is:
Find the Principal Argument of z = 3 + i z = \sqrt{3} + i z = 3 + i
The point ( 3 , 1 ) (\sqrt{3}, 1) ( 3 , 1 ) is in Quadrant .
Two complex numbers z 1 = r 1 ( cos θ 1 + i sin θ 1 ) z_1 = r_1(\cos \theta_1 + i\sin \theta_1) z 1 = r 1 ( cos θ 1 + i sin θ 1 ) and z 2 = r 2 ( cos θ 2 + i sin θ 2 ) z_2 = r_2(\cos \theta_2 + i\sin \theta_2) z 2 = r 2 ( cos θ 2 + i sin θ 2 ) are said to be equal if and only if:
Their moduli are equal:
r 1 = r 2 r_1 = r_2 r 1 = r 2 (or ∣ z 1 ∣ = ∣ z 2 ∣ |z_1| = |z_2| ∣ z 1 ∣ = ∣ z 2 ∣ )
Their arguments are the same or differ by a multiple of 2 π 2\pi 2 π (or 360 ∘ 360^\circ 36 0 ∘ ):
θ 1 = θ 2 + 2 k π \theta_1 = \theta_2 + 2k\pi θ 1 = θ 2 + 2 k π or for
some integer .
If we use the Principal Argument (with the range [ 0 , 2 π ) [0, 2\pi) [ 0 , 2 π ) ), the second condition simplifies to: Arg ( z 1 ) = Arg ( z 2 ) \text{Arg}(z_1) = \text{Arg}(z_2) Arg ( z 1 ) = Arg ( z 2 ) .
Determine if the following pairs of complex numbers are equal or different?
z 1 = 2 ( cos 45 ∘ + i sin 45 ∘ ) z_1 = \sqrt{2}(\cos 45^\circ + i\sin 45^\circ) z 1 = 2 ( cos 4 5 ∘ + i sin 4 5 ∘ ) and z 2 = 2 ( cos 95 ∘ + i sin 95 ∘ ) z_2 = \sqrt{2}(\cos 95^\circ + i\sin 95^\circ) z 2 = 2 ( cos 9 5 ∘ + i sin 9 5 ∘ )
z 1 = cos 30 ∘ + i sin 30 ∘ z_1 = \cos 30^\circ + i\sin 30^\circ z 1 = cos 3 0 ∘ + i sin 3 0 ∘ and z 2 = cos 390 ∘ + i sin 390 ∘ z_2 = \cos 390^\circ + i\sin 390^\circ z 2 = cos 39 0 ∘ + i sin 39 0 ∘
Consider:
Modulus: ∣ z 1 ∣ = 2 |z_1| = \sqrt{2} ∣ z 1 ∣ = 2 and ∣ z 2 ∣ = 2 |z_2| = \sqrt{2} ∣ z 2 ∣ = 2 . (Equal)
Principal Argument: Arg ( z 1 ) = 45 ∘ \text{Arg}(z_1) = 45^\circ Arg ( z 1 ) = 4 5 ∘ and Arg ( z 2 ) = 95 ∘ \text{Arg}(z_2) = 95^\circ Arg ( z 2 ) = 9 5 ∘ . (Different)
Since their principal arguments are different (45 ∘ ≠ 95 ∘ 45^\circ \neq 95^\circ 4 5 ∘ = 9 5 ∘ ), then z 1 ≠ z 2 z_1 \neq z_2 z 1 = z 2 .
Consider:
Modulus: ∣ z 1 ∣ = 1 |z_1| = 1 ∣ z 1 ∣ = 1 and ∣ z 2 ∣ = 1 |z_2| = 1 ∣ z 2 ∣ = 1 . (Equal)
Find the Principal Argument (in degrees) for the following complex numbers:
1 + 3 i 1 + \sqrt{3}i 1 + 3 i
− i -i − i
For z = 1 + 3 i z = 1 + \sqrt{3}i z = 1 + 3 i :
The point ( 1 , 3 ) (1, \sqrt{3}) ( 1 , 3 ) is in Quadrant I I I .
Since 60 ∘ ∈ [ 0 ∘ , 360 ∘ ) 60^\circ \in [0^\circ, 360^\circ) 6 0 ∘ ∈ [ 0 ∘ , 36 0 ∘ ) , then Arg ( z ) = 60 ∘ \text{Arg}(z) = 60^\circ Arg ( z ) = 6 0 ∘ .
For z = − i z = -i z = − i :
Can be written as z = 0 − 1 i z = 0 - 1i z = 0 − 1 i . The point ( 0 , − 1 ) (0, -1) ( 0 , − 1 ) is on the negative imaginary axis.
Since 30 ∘ 30^\circ 3 0 ∘ is already within the range [ 0 ∘ , 360 ∘ ) [0^\circ, 360^\circ) [ 0 ∘ , 36 0 ∘ ) , the Principal Argument is:
θ 1 − θ 2 = 2 k π \theta_1 - \theta_2 = 2k\pi θ 1 − θ 2 = 2 k π Arguments: θ 1 = 30 ∘ \theta_1 = 30^\circ θ 1 = 3 0 ∘ and θ 2 = 390 ∘ \theta_2 = 390^\circ θ 2 = 39 0 ∘ . Difference of arguments: θ 1 − θ 2 = 30 ∘ − 390 ∘ = − 360 ∘ \theta_1 - \theta_2 = 30^\circ - 390^\circ = -360^\circ θ 1 − θ 2 = 3 0 ∘ − 39 0 ∘ = − 36 0 ∘ . Since the difference of the arguments is a multiple of 360 ∘ 360^\circ 36 0 ∘ (− 360 ∘ = − 1 × 360 ∘ -360^\circ = -1 \times 360^\circ − 36 0 ∘ = − 1 × 36 0 ∘ ), then z 1 = z 2 z_1 = z_2 z 1 = z 2 .
Alternatively, we can see that the Principal Argument of z 2 z_2 z 2 is 390 ∘ − 360 ∘ = 30 ∘ 390^\circ - 360^\circ = 30^\circ 39 0 ∘ − 36 0 ∘ = 3 0 ∘ , which is the same as the Principal Argument of z 1 z_1 z 1 .
The argument is 270 ∘ 270^\circ 27 0 ∘ (or − 90 ∘ -90^\circ − 9 0 ∘ ).
Since we are looking for the Principal Argument in the range [ 0 ∘ , 360 ∘ ) [0^\circ, 360^\circ) [ 0 ∘ , 36 0 ∘ ) , then Arg ( z ) = 270 ∘ \text{Arg}(z) = 270^\circ Arg ( z ) = 27 0 ∘ .