Sarrus' method is a practical way to calculate the determinant of a 3×3 matrix. This method is named after Pierre Frédéric Sarrus. To understand it, let's recall how to calculate the determinant of a 2×2 matrix.
If we have a 2×2 matrix:
M=[acbd]
Its determinant, det(M) or ∣M∣, is calculated as follows:
det(M)=ad−bc
This is the difference between the product of the main diagonal elements (ad) and the product of the secondary diagonal elements (bc). Sarrus' method adapts this principle for 3×3 matrices.
The first term is the product of the main diagonal. The second and third terms are products of parallel diagonals involving elements from the copied columns.
Step3: Calculate the Sum of the Products of the Negative Diagonals
Multiply the elements along the three diagonals from the top-right to the bottom-left. Sum these products, let's call it Dnegative.
The first term is the product of the secondary diagonal (anti-diagonal). The second and third terms are products of parallel diagonals involving elements from the copied columns, moving towards the bottom-left.
Step4: Calculate the Final Determinant
The determinant of matrix A, det(A), is the difference between Dpositive and Dnegative:
det(A)=Dpositive−Dnegative
Substitute the values of Dpositive and Dnegative:
Sarrus' method is only applicable to 2×2 and 3×3 matrices. For matrices of higher order (e.g., 4×4), this method cannot be used. Other methods such as cofactor expansion or row reduction are required for such cases.