A basket contains duck eggs and chicken eggs. Half of the duck eggs are broken, and one-fourth of the chicken eggs are broken.
If one egg is taken from the basket, what is the probability that the taken egg is a duck egg or a broken egg?
Search for a command to run...
A basket contains 10 duck eggs and 20 chicken eggs. Half of the duck eggs are broken, and one-fourth of the chicken eggs are broken.
If one egg is taken from the basket, what is the probability that the taken egg is a duck egg or a broken egg?
Let's define the events as follows:
First, we calculate the total number of eggs in the basket:
Next, we calculate the number of broken eggs:
The total number of broken eggs (n(B)) is:
We are asked to find the probability of picking a duck egg or a broken egg (D∪B). The formula for the probability of the union of two events is:
Where n(D∪B) can be calculated using the inclusion-exclusion principle:
Thus:
So the probability is:
Therefore, the probability of picking a duck egg or a broken egg is 0.5.