Given a sequence b1,b2,b3,….
If bn+2=bn+1−3bn, and b4=5 and b5=−1, then the value of b2 is ....
Explanation
Given the recursive formula of the sequence is bn+2=bn+1−3bn. We also know the values b4=5 and b5=−1. We are asked to find the value of b2. We will find it by working backwards from b5 to b3, and then to b2.
Finding the Value of b3
Use the formula with n=3:
b3+2=b3+1−3b3
b5=b4−3b3
Substitute the values b5=−1 and b4=5:
−1=5−3b3
3b3=5+1
3b3=6
b3=2
Finding the Value of b2
Use the formula with n=2:
b2+2=b2+1−3b2
b4=b3−3b2
Substitute the values b4=5 and b3=2:
5=2−3b2
3b2=2−5
3b2=−3
b2=−1
So, the value of b2 is −1.