Problem 13

Explanation

First, we find the actual width of the field. Given the area of the field $L = 384\text{ m}^2$ and length $p = 32\text{ m}$. Then the actual width ($l$) is:

Next, we convert the actual width to cm to match the drawing unit.

Finally, we calculate the width of the field in the drawing using the scale ratio $3 : 600$.

So, the width of the field in the drawing is $6\text{ cm}$.