If f(x)=2x+3 and 3f2(x)=f(x)+7 are satisfied by x1 and x2, then the value of x1+x2= ...
Explanation
We are given the function f(x)=2x+3 and the equation 3f2(x)=f(x)+7. We want to find the sum of the roots of the equation, which is x1+x2.
Substituting the Function
The first step is to substitute f(x) into the given equation.
3(2x+3)2=(2x+3)+7
Simplifying the Equation
Next, we expand the square and simplify the equation into the general quadratic form ax2+bx+c=0.
3(4x2+12x+9)=2x+10
12x2+36x+27=2x+10
Move all terms to the left side:
12x2+36x−2x+27−10=0
12x2+34x+17=0
Using the Sum of Roots Formula
From the quadratic equation 12x2+34x+17=0, we obtain the coefficients:
- a=12
- b=34
- c=17
The sum of the roots of a quadratic equation can be calculated using the formula x1+x2=−ab.
x1+x2=−1234
Simplify the fraction by dividing the numerator and denominator by 2:
x1+x2=−617
Conclusion
Thus, the value of x1+x2 is −617.