2Number 2ExplanationA piece of wood weighs 909090 grams. After being dried in the sun, it weighs 606060 grams. What is the percentage of water content in the wet wood?80%80\%80%40%40\%40%3313%33\frac{1}{3}\%3331%25%25\%25%20%20\%20%ExplanationGiven: Initial weight (wet wood) = 909090 grams. Final weight (dry wood) = 606060 grams. The water content in the wood is the difference between the initial weight and the final weight: Water Weight=90−60=30 grams\text{Water Weight} = 90 - 60 = 30 \text{ grams}Water Weight=90−60=30 grams The percentage of water content is calculated relative to the initial weight (wet wood): Percentage=Water WeightInitial Weight×100%\text{Percentage} = \frac{\text{Water Weight}}{\text{Initial Weight}} \times 100\%Percentage=Initial WeightWater Weight×100%=3090×100%= \frac{30}{90} \times 100\%=9030×100%=13×100%= \frac{1}{3} \times 100\%=31×100%=3313%= 33\frac{1}{3}\%=3331% Therefore, the water content in the wet wood is 3313%33\frac{1}{3}\%3331%.
