Given an is the n-th term of a sequence of numbers. If an=an+1+3an+3, a1=−1, and a2=2, then the value of a4+a1 is
Explanation
We are given a recursive formula for a sequence of numbers:
an=an+1+3an+3
We also know that a1=−1 and a2=2. We are asked to find the value of a4+a1.
Determining the Value of the Fourth Term
To find a4, we can use the given equation by substituting n=1:
a1a1=a1+1+3a1+3=a2+3a4
Next, we substitute the values a1=−1 and a2=2 into the equation:
−13a43a4a4a4=2+3a4=−1−2=−3=3−3=−1
Calculating the Sum
Now that we have found a4=−1, we can calculate a4+a1:
a4+a1=(−1)+(−1)=−2
So, the value of a4+a1 is −2.