The fractional form of the repeating decimal 3.15931593... is?
Explanation
Let x=3.15931593....
Since there are 4 repeating digits (which are 1593), we multiply x by 10000:
10000x=31593.15931593...
Next, we subtract the original equation x from this equation:
10000xx9999x=31593.1593...=31593.1593...=31590
Thus, we obtain:
x=999931590
We simplify the fraction by dividing both the numerator and the denominator by 9:
x=9999÷931590÷9=11113510