For the function f(x)=x2+x−65−x to be defined in its domain, the domain of function f is...
Explanation
To find the domain of the function, we need to ensure that all components of the function are defined (values inside square roots must be non-negative, and the denominator cannot be zero).
The function f(x)=x2+x−65−x has two main conditions:
Condition 1: Numerator
The value inside the square root in the numerator must be non-negative:
Condition 2: Denominator
The value inside the square root in the denominator must be positive (since the square root in the denominator cannot be zero):
The zeros of this inequality are x=−3 and x=2.
Using test points, we find the solution region for the denominator: x<−3 or x>2.
Domain Intersection
The domain of function f is the intersection of the two conditions above:
- x≤5
- x<−3 or x>2
The intersection is:
- For x<−3, it satisfies x≤5.
- For x>2, it is bounded by x≤5, becoming 2<x≤5.
Therefore, the domain of function f is: