If the tangent line to the curve y=x3−3x2−9x at point (a,b) has a gradient of 15, then the possible value of a+b is....
Explanation
Substitute point (a,b) into (x,y) in the equation
Find the first derivative
Remember the concept that the first derivative of a function equals the gradient of the line
Determine the value of b from equation (1) and a+b
When a=−2
When a=4
Following the available options, the answer is −4.
Given x2+2xy+4x=−3 and 9y2+4xy+12y=−1. The value of x+3y is....
Explanation
Add the two equations
Since we are asked for the value of x+3y, we use the substitution x+3y=p
Apply factorization
Take the square root of both sides
This means x+3y=p→x+3y=−2.
If an integer p is a root of f(x)=0 with f(x)=px2−3x−p−3, then the gradient of the tangent line to the curve y=f(x) at the point with abscissa x=p is....
Explanation
The integer p is a root of f(x)=0. We can conclude that x=p so f(p)=0
The factorization above is obtained using Horner's method.
Since the form p2−p−3=0 cannot be factored further, we only obtain p=−1. Thus the function becomes
With x=p=−1, the gradient is
If (p,q) is the vertex point of the graph of function f(x)=ax2+2ax+a+1, with f(a)=19, then p+2q+3a=....
Explanation
Given f(a)=19 then
Factor using Horner's method to get
Thus we obtain a=2, and the quadratic function becomes
Vertex point p
Therefore the value of p+2q+3a is
Given a straight line passing through (0,−2) and (23,0). The distance from the parabola y=x2−1 to that line is....
Explanation
Create the equation of the line from the points it passes through, namely (0,−2) and (23,0)
We cannot directly find the distance from a point to the line. Find the point whose position is closest to the line. Assume the point is (a,b) so that
The point becomes (a,a2−1) as shown in the following illustration
We need to determine the distance from point (a,a2−1) to the line −4x+3y+6=0
The condition for minimum value is f′(x)=0
Distance between line and parabola when a=32
Given a sequence −21,43,−81,163,..., the 12th term of this sequence is....
Explanation
The given sequence can be written as
We can simplify it into a general form where
For odd n, the nth term is un=−2n1
For even n, the nth term is un=2n3
Therefore, the 12th term or even term is
Given a sequence 0,43,163,649,..., then the 12th term of this sequence is....
Explanation
Given sequence
Each term if expanded becomes
Therefore, the nth term can be formulated as follows
Then the 12th term is
Given a sequence 0,65,365,21635,..., the 12th term of this sequence is....
Explanation
Given sequence
Each term if expanded becomes
Therefore, the nth term can be formulated as follows
Then the 12th term is
A geometric sequence has 3 first terms a,b,b2. If a and b are roots of the quadratic equation 2x2+kx+6=0, then the fourth term of the sequence and the value of k respectively are....
Explanation
A geometric sequence has a ratio between its terms, or the value of the ratio between terms
The quadratic equation 2x2+kx+6=0 has roots x1=a=1 and x2=b
Product of roots
Sum of roots
Therefore the geometric sequence is
Then the 4th term is
Thus the values of u4 and k respectively are 27 and −8.
Suppose x1 and x2 are integers that are roots of the quadratic equation x2−(2k+4)x+(3k+4)=0. If x1,k,x2 form the first three terms of a geometric series, then the formula for the nth term of the series is....
Explanation
Given quadratic equation
With roots x1 and x2, the product of roots is
So the geometric sequence is x1,k,x2.
The ratio between terms is
Factorize
Determine the form of the quadratic equation based on the obtained value of k.
k=4Check the discriminant value, the roots are not integers.
k=−1Therefore the sequence is
The ratio between terms is
Then the nth term of the sequence is
Explanation
Given f(x)=sin2x. If f′(x) represents the first derivative of f(x), then
Explanation
Given
Asked
Let h1=a; h→∞ so the value a→0.
Since f(x)=sin2x, then
Therefore, the value of
Given f(x)=1+x. The value of limh→0h2f(3+2h2)−f(3−3h2) is....
Explanation
First find the derivative of the function
If y=f(g(x)) then the first derivative is y′=g′(x)⋅f′(g(x)). Check the limit value
Then we use another method, L'Hospital's rule or the first derivative
Explanation
Recall that tanx=cosxsinx
Factor it
Common denominator
If limx→−3bx3+27ax1+31=−351, the value of a+b for a and b positive integers is....
Explanation
Common denominator in the numerator
For x=−3 then
Substitute x=−3 into the denominator
Therefore the value of a+b=1+1=2.
If loga2(3a−8)−4⋅log3a=a−2, then loga(81)=....
Explanation
Let 3a=p>0 then we can transform the equation into
Convert logarithmic form to exponential form
Substitute the value p=9
Therefore
If (log2x)2−(log2y)2=log2256 and log2x2−log2y2=log216. Then the value of log2x6y−2 is....
Explanation
Use the substitution log2x=a and log2y=b. Then transform the logarithm equation into
Convert to exponential form
Substitute equation (1)
Therefore the result from equation (1) is a=b+2=1+2=3.
Determine the value of log2x6y−2
If 2log4x−log4(4x+3)=−1, then log2x=....
Explanation
The requirement for logarithm logab is that a>0. Therefore
Where the value x>0.
Determine the value of x
Factor
Since the requirement is x>0, then x=23 satisfies. Therefore
If a satisfies the equation log22x+log33x=log44x2, then the value of loga3=....
Explanation
Recall some logarithm concepts
And also logambn=mn⋅logab.
Let's simplify the logarithm form
Therefore the solution is x=a so
If α and β are roots of the equation log3x−logx(2x−4+x4)=1, then α+β=....
Explanation
Transform the equation to exponential form
Therefore the sum of the roots is
If b>a, the value of x that satisfies ∣x−2a∣+a≤b is....
Explanation
Solve the inequality
Add 2a to both sides
Therefore the solution is −b+3a≤x≤b+a.
The solution set of 9−x2≥∣x+3∣ is....
Explanation
The absolute value has the definition
Solve the inequality
For x≥−3
Create the number line
From the condition x≥−3 and the number line region above, the solution set is {−3≤x≤2}.
For x<−3
The number line
From the condition x<−3 and the second number line region above, the solution set is an empty set.
Therefore the combined solution is
The solution set of 16−x2≤∣x+4∣ is....
Explanation
The absolute value has the definition
Solve the inequality
For x≥−4
Create the number line
From the condition x≥−4 and the number line region above, the solution set is {x≤−4∨x≥3}.
For x<−4
The number line
From the condition x<−4 and the second number line region above, the solution set is {x<−4}.
Therefore the combined solution is
The solution set of inequality log∣x+1∣≥log3+log∣2x−1∣ is....
Explanation
The logarithm conditions are
Recall some basic concepts of absolute value inequality
With condition a>1.
Let's solve the inequality
The solution
The number line
Therefore the solution is
The number of real numbers x that satisfy the equation ∣x2−4∣=x+∣x−2∣ is....
Explanation
Define the first absolute value for ∣x−2∣.
x−2 is positive for x−2≥0→x≥0.
x−2 is negative for x−2<0→x<2.
So the definition is
For ∣x2−4∣
x2−4 is positive for x2−4≥0→x≤−2∨x≥0.
x2−4 is negative for x2−4<0→−2<x<2.
So the definition is
Based on the definitions above, the absolute value is bounded by x=−2 and x=2. This means there are 3 possible regions/values of x.
Solve the problem based on regions.
Region I when x<−2
Since region I is negative, the root that satisfies is x1=−6.
Region II when −2≤x<2
Since region II includes both positive and negative, all roots satisfy region II.
Region III when x≥2
Determine the discriminant value to find the type of roots.
Since D>0, the roots are distinct, one positive root satisfies region III.
Therefore the total number of solutions is 4 solutions.