Given that the polynomial when divided by leaves a remainder of , and when divided by leaves a remainder of . If , then = ....
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Given that the polynomial f(x) when divided by x2+x−2 leaves a remainder of ax+b, and when divided by x2−4x+3 leaves a remainder of 2bx+a−1. If f(−2)=7, then a2+b2 = ....
The first polynomial has divisor x2+x−2. Factor the divisor
The remainder is s(x)=ax+b.
When x=1
When x=−2
The second polynomial has divisor x2−4x+3. Factor the divisor
The remainder is s(x)=2bx+a−1.
When x=1
When x=3
From equations (1) and (3) we obtain
From equation (2) and given f(−2)=7, then
Substitute b=1 into equation (5)
So the value of