The roots of the equation form a geometric sequence with ratio . The value of is....
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The roots of the equation x3−7x2+px+q=0 form a geometric sequence with ratio 2. The value of p+q is....
Let the polynomial x3−7x2+px+q=0 have roots x1,x2,x3. The sequence formed is geometric with ratio 2. So it can be assumed that x1=k, x2=2k, x3=4k. Or the values a=k and r=2. If ordered x1=a=k, x2=ar=2k, x3=ar2=k⋅22=4k.
The polynomial consecutively has values a=1, b=−7, c=p, d=q. Then the sum of the roots of the polynomial
The value x1=k=1 is obtained. Substitute x=1 into the polynomial equation