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Nabil Akbarazzima Fatih

Mathematics

Relationship Between Exponents and Radicals

Radical forms and exponents are closely related. When we have a number with a fractional exponent, we can convert it to a radical form.

Consider the following exponential function:

f(x)=50(0.5)xf(x) = 50(0.5)^x

This function represents the decay of drug dosage in a patient's body, where xx is the time needed for the drug to decay by half of its previous dosage.

If we want to know the amount of dosage that decays after 30 minutes, we substitute x=30x = 30 into the function.

f(30)=50(0.5)30f(30) = 50(0.5)^{30}

For a time of half an hour, we can write the fractional exponent form:

f(12)=50(0.5)12f\left(\frac{1}{2}\right) = 50(0.5)^{\frac{1}{2}}

The fractional exponent (0.5)12(0.5)^{\frac{1}{2}} is difficult to calculate manually. Therefore, we need an equivalent form.

Another form of (0.5)12(0.5)^{\frac{1}{2}} is 0.5\sqrt{0.5}. This is what we call a radical form.

Definition of Radical Form

The radical form is defined for any rational exponent mn\frac{m}{n}, where mm and nn are integers and n>0n > 0:

amn=(an)m or amn=amna^{\frac{m}{n}} = (\sqrt[n]{a})^m \text{ or } a^{\frac{m}{n}} = \sqrt[n]{a^m}

This allows us to convert numbers with fractional exponents to radical form and vice versa.

Simplifying Radical Forms

Here's an example of simplifying the multiplication of two radical forms:

Simplify the expression (2x)(3x3)(2\sqrt{x})(3\sqrt[3]{x}) for x>0x > 0

(2x)(3x3)=(2x12)(3x13)=23x12+13=6x3+26=6x56=6x56\begin{align} (2\sqrt{x})(3\sqrt[3]{x}) &= (2x^{\frac{1}{2}})(3x^{\frac{1}{3}}) \\ &= 2 \cdot 3 \cdot x^{\frac{1}{2} + \frac{1}{3}} \\ &= 6x^{\frac{3+2}{6}} \\ &= 6x^{\frac{5}{6}} \\ &= 6\sqrt[6]{x^5} \end{align}

Therefore, the simplified form is 6x566x^{\frac{5}{6}} or 6x566\sqrt[6]{x^5}.

Important Property of Radical Forms

It's important to understand that the form a+b=a+b\sqrt{a+b} = \sqrt{a} + \sqrt{b} is not correct.

Let's take the values a=4a = 4 and b=9b = 9, then:

4+9=134+9=2+3=5\sqrt{4 + 9} = \sqrt{13} \neq \sqrt{4} + \sqrt{9} = 2 + 3 = 5

Another example:

16+9=25=5\sqrt{16 + 9} = \sqrt{25} = 5
16+9=4+3=7\sqrt{16} + \sqrt{9} = 4 + 3 = 7

Since 575 \neq 7, it's clear that a+ba+b\sqrt{a+b} \neq \sqrt{a} + \sqrt{b}.