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Nabil Akbarazzima Fatih

Mathematics

Understanding Linear Inequality Systems

In everyday life, we often face situations with various constraints to consider. For example, when baking, we might be limited by the amount of available ingredients and our budget. These types of constraints can often be modeled using linear inequalities.

What Is a Linear Inequality System?

A linear inequality system is a collection of two or more linear inequalities that must be satisfied simultaneously. Linear inequalities take the form:

a1x1+a2x2+...+anxnb or a1x1+a2x2+...+anxnba_1x_1 + a_2x_2 + ... + a_nx_n \leq b \text{ or } a_1x_1 + a_2x_2 + ... + a_nx_n \geq b

Where a1,a2,...,ana_1, a_2, ..., a_n are coefficients, x1,x2,...,xnx_1, x_2, ..., x_n are variables, bb is a constant, and the inequality sign can be ,,<,>\leq, \geq, <, >.

The main difference between linear equations and linear inequalities is:

  • Linear equations have exactly one equals sign (==)
  • Linear inequalities have an inequality sign (,,<,>\leq, \geq, <, >)

Linear Inequality Systems with Two Variables

A linear inequality system with two variables consists of two or more inequalities with two variables (usually xx and yy):

{a1x+b1yc1a2x+b2yc2\begin{cases} a_1x + b_1y \leq c_1 \\ a_2x + b_2y \leq c_2 \end{cases}

Example:

{2x+5y<106x+2y>10\begin{cases} 2x + 5y < 10 \\ 6x + 2y > 10 \end{cases}

The solution to this system is the set of ordered pairs (x,y)(x,y) that satisfy all inequalities simultaneously.

Solving Linear Inequality Systems

To solve a linear inequality system with two variables, we use the graphical method with the following steps:

Draw the Boundary Lines

For each inequality, draw its boundary line by changing the inequality sign to an equals sign.

Example:

For the system:

{2x+5y<106x+2y>10\begin{cases} 2x + 5y < 10 \\ 6x + 2y > 10 \end{cases}

Draw the lines:

{2x+5y=106x+2y=10\begin{cases} 2x + 5y = 10 \\ 6x + 2y = 10 \end{cases}

Determine the Solution Regions

To determine the solution region for each inequality:

  1. Take a test point (e.g., the origin (0,0)(0,0) if it's not on the line)
  2. Substitute it into the inequality
  3. If the result is true, the region containing the test point is the solution region
  4. If the result is false, the region not containing the test point is the solution region

Example:

For 2x+5y<102x + 5y < 10, check point (0,0):

2(0)+5(0)=0<102(0) + 5(0) = 0 < 10

(true)

The solution region is the area containing point (0,0), which is below the line 2x+5y=102x + 5y = 10.

For 6x+2y>106x + 2y > 10, check point (0,0):

6(0)+2(0)=0>106(0) + 2(0) = 0 > 10

(false)

The solution region is the area not containing point (0,0), which is above the line 6x+2y=106x + 2y = 10.

Determine the Intersection of Solution Regions

The solution to the linear inequality system is the intersection (the area satisfied by all constraints) of all the solution regions involved.

Graphical Representation

When drawing inequality graphs:

  • For \leq or \geq: use a solid line (the solution region includes points on the line)
  • For << or >>: use a dashed line (the solution region does not include points on the line)
  • The solution region is shaded to show the solution

Real-life Applications

Mathematical Modeling

Linear inequality systems are very useful for modeling optimization problems, such as:

  • Production problems with resource constraints
  • Budget planning with cost constraints
  • Nutrition planning with calorie constraints

Activity Planning

Kiki is organizing an independence day celebration in her neighborhood. From the community fund, there is Rp500,000.00 available. For organizing competitions, it costs Rp20,000.00 per child. Prizes for winners are budgeted at Rp40,000.00 for each type of competition. It's expected that more than 13 children will participate.

Let's define:

  • xx = number of participants
  • yy = number of competitions

The mathematical model is:

{20.000x+40.000y500.000x>13\begin{cases} 20.000x + 40.000y \leq 500.000 \\ x > 13 \end{cases}

If we simplify:

{20x+40y500x>13\begin{cases} 20x + 40y \leq 500 \\ x > 13 \end{cases}

The solution to this system is the region that satisfies both inequalities. From the graph, we can see various combinations of participants and competitions that can be organized within budget constraints.

Problem-Solving Strategy

To solve linear inequality system problems:

  1. Identify the variables to use
  2. Create a mathematical model based on the given constraints
  3. Solve the system using the graphical method
  4. Interpret the solution in the context of the original problem

Differences Between Linear Equation Systems and Linear Inequality Systems

AspectLinear Equation SystemsLinear Inequality Systems
Operation SignUses equals sign (==)Uses inequality signs (<,>,,<, >, \leq, \geq)
Solution FormUsually a point or set of pointsA region on the coordinate plane
Graphical RepresentationIntersection of linesIntersection of shaded regions
Solution MethodsSubstitution, elimination, determinantsPrimarily graphical method
Number of SolutionsCan have one solution, infinite solutions, or no solutionUsually has infinite solutions (a region)
DrawingAlways uses solid linesSolid lines for ,\leq, \geq and dashed lines for <,><, >

Interactive Visualization of Linear Inequality Systems

Let's imagine a linear inequality system as boundary fences in a garden. Each inequality limits which areas we can enter. When there's more than one inequality, we can only be in areas that satisfy all constraints.

Here's an interactive visualization of a linear inequality system to help us understand this concept better:

Example of an Inequality System

Consider the following linear inequality system:

{x+y1015x+9y120\begin{cases} x + y \leq 10 \\ 15x + 9y \geq 120 \end{cases}

In the visualization below, the blue region shows the solution to x+y10x + y \leq 10 (all points below or on the line x+y=10x + y = 10).

The red region shows the solution to 15x+9y12015x + 9y \geq 120 (all points above or on the line 15x+9y=12015x + 9y = 120).

The purple region (the intersection of the blue and red areas) is the solution to the linear inequality system.

Linear Inequality System
Visualization of the system of inequalities x + y ≤ 10 and 15x + 9y ≥ 120.

How to Read the Visualization

In this interactive visualization:

  1. Boundary lines show the equations (e.g., x+y=10x + y = 10 and 15x+9y=12015x + 9y = 120)
  2. Colored regions show the solution to each inequality
  3. Intersection region (the area satisfying all inequalities) is the solution to the inequality system

You can clearly see that the solution to this inequality system forms a region bounded by both lines. From the visualization, we can also determine the intersection point of the two lines, which is an important point in the solution region.

By understanding this visualization, you'll find it easier to solve optimization problems in everyday life involving constraints that can be modeled with linear inequality systems.