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Circle

External Tangent Line and Internal Tangent Line

Definition of Common Tangent Lines

A common tangent line is a line that touches two circles simultaneously. There are two types of common tangent lines:

  1. External Common Tangent Line: A line that touches both circles from the same side
  2. Internal Common Tangent Line: A line that touches both circles from opposite sides

Concept of External Common Tangent Line

An external common tangent line is a line that touches both circles and does not intersect the line connecting the two circle centers.

External Common Tangent Line
Two external common tangent lines on two circles.

Formula for External Common Tangent Line Length

For two circles with:

  • First circle center: O1O_1
  • Second circle center: O2O_2
  • First circle radius: r1r_1
  • Second circle radius: r2r_2
  • Distance between centers: dd

Length of external common tangent line:

l=d2(r2r1)2l = \sqrt{d^2 - (r_2 - r_1)^2}

Finding the Length of External Common Tangent Line

Two circles are centered at A(3,0)A(-3, 0) with radius 1.5 and B(3,0)B(3, 0) with radius 2.5. Find the length of the external common tangent line!

Circles with r1=1.5r_1 = 1.5 and r2=2.5r_2 = 2.5
Visualization of external common tangent line.

Solution:

d=(3(3))2+(00)2=36=6d = \sqrt{(3-(-3))^2 + (0-0)^2} = \sqrt{36} = 6
l=d2(r2r1)2l = \sqrt{d^2 - (r_2 - r_1)^2}
l=62(2.51.5)2l = \sqrt{6^2 - (2.5 - 1.5)^2}
l=361l = \sqrt{36 - 1}
l=35l = \sqrt{35}

Therefore, the length of the external common tangent line is 35\sqrt{35} units.

Concept of Internal Common Tangent Line

An internal common tangent line is a line that touches both circles from opposite sides and intersects the line connecting the two circle centers.

Internal Common Tangent Line
Two internal common tangent lines on two circles.

Formula for Internal Common Tangent Line Length

Length of internal common tangent line:

l=d2(r1+r2)2l = \sqrt{d^2 - (r_1 + r_2)^2}

Condition: Internal common tangent lines exist only if d>r1+r2d > r_1 + r_2 (the two circles do not intersect).

Finding the Length of Internal Common Tangent Line

Two circles are centered at P(5,0)P(-5, 0) with radius 2 and Q(5,0)Q(5, 0) with radius 3. Find the length of the internal common tangent line!

Circles with r1=2r_1 = 2 and r2=3r_2 = 3
Visualization of internal common tangent line.

Solution:

First, check if internal common tangent lines exist:

d=(5(5))2+(00)2=100=10d = \sqrt{(5-(-5))^2 + (0-0)^2} = \sqrt{100} = 10
r1+r2=2+3=5r_1 + r_2 = 2 + 3 = 5
d=10>5=r1+r2 d = 10 > 5 = r_1 + r_2 \space \checkmark

Since the condition is satisfied, then:

l=d2(r1+r2)2l = \sqrt{d^2 - (r_1 + r_2)^2}
l=10252l = \sqrt{10^2 - 5^2}
l=10025l = \sqrt{100 - 25}
l=75l = \sqrt{75}
l=53l = 5\sqrt{3}

Therefore, the length of the internal common tangent line is 535\sqrt{3} units.

Circles with Equal Radii

When two circles have equal radii (r1=r2=rr_1 = r_2 = r), there are special properties:

External Common Tangent Line

External Common Tangent Line for Equal Radii
External common tangent lines are parallel to the line of centers.

For r1=r2r_1 = r_2:

  • External common tangent lines are parallel to the line connecting the two centers
  • Length of external common tangent line = dd (distance between centers)

Cases of Various Circle Positions

Determine the length of external and internal common tangent lines for the following circles:

Distant Circles

The first circle is centered at (6,0)(-6, 0) with radius 1, the second circle is centered at (6,0)(6, 0) with radius 2.

Case: Distant Circles
Both types of common tangent lines exist.

Solution:

d=(6(6))2+(00)2=12d = \sqrt{(6-(-6))^2 + (0-0)^2} = 12
lexternal=122(21)2=1441=143l_{external} = \sqrt{12^2 - (2-1)^2} = \sqrt{144 - 1} = \sqrt{143}
linternal=122(1+2)2=1449=135=315l_{internal} = \sqrt{12^2 - (1+2)^2} = \sqrt{144 - 9} = \sqrt{135} = 3\sqrt{15}

Close Circles

The first circle is centered at (2,0)(-2, 0) with radius 1.5, the second circle is centered at (2,0)(2, 0) with radius 1.5.

Case: Close Circles with Equal Radii
External common tangent lines are parallel, internal ones intersect at the center.

Solution:

d=(2(2))2+(00)2=4d = \sqrt{(2-(-2))^2 + (0-0)^2} = 4
r1=r2=1.5r_1 = r_2 = 1.5
lexternal=d=4l_{external} = d = 4
linternal=42(1.5+1.5)2=169=7l_{internal} = \sqrt{4^2 - (1.5+1.5)^2} = \sqrt{16 - 9} = \sqrt{7}

Practice Problems

  1. Two circles are centered at A(4,0)A(-4, 0) with radius 2 and B(4,0)B(4, 0) with radius 3. Determine:

    • Length of external common tangent line
    • Length of internal common tangent line
  2. The first circle has center (0,0)(0, 0) with radius 4, the second circle has center (10,0)(10, 0) with radius 2. Calculate the length of both types of common tangent lines!

  3. Two identical circles each have radius 3 cm. If the length of the internal common tangent line is 8 cm, determine the distance between the two circle centers!

  4. Circle AA is centered at (5,0)(-5, 0) with radius rr, and circle BB is centered at (7,0)(7, 0) with radius 2r2r. If the length of the external common tangent line is 484\sqrt{8}, determine the value of rr!

  5. Determine the conditions for two circles to have:

    • Exactly two common tangent lines
    • Exactly three common tangent lines
    • Exactly four common tangent lines

Answer Key

  1. Calculating common tangent line lengths

    d=(4(4))2+(00)2=8d = \sqrt{(4-(-4))^2 + (0-0)^2} = 8
    lexternal=82(32)2=641=63=37l_{external} = \sqrt{8^2 - (3-2)^2} = \sqrt{64 - 1} = \sqrt{63} = 3\sqrt{7}
    linternal=82(2+3)2=6425=39l_{internal} = \sqrt{8^2 - (2+3)^2} = \sqrt{64 - 25} = \sqrt{39}
  2. Circles with different centers

    d=(100)2+(00)2=10d = \sqrt{(10-0)^2 + (0-0)^2} = 10
    lexternal=102(42)2=1004=96=46l_{external} = \sqrt{10^2 - (4-2)^2} = \sqrt{100 - 4} = \sqrt{96} = 4\sqrt{6}
    linternal=102(4+2)2=10036=64=8l_{internal} = \sqrt{10^2 - (4+2)^2} = \sqrt{100 - 36} = \sqrt{64} = 8
  3. Finding center distance from internal tangent length

    Given: r1=r2=3r_1 = r_2 = 3, linternal=8l_{internal} = 8

    l=d2(r1+r2)2l = \sqrt{d^2 - (r_1 + r_2)^2}
    8=d2628 = \sqrt{d^2 - 6^2}
    64=d23664 = d^2 - 36
    d2=100d^2 = 100
    d=10 cmd = 10 \text{ cm}
  4. Finding the value of r

    Given: d=12d = 12, r1=rr_1 = r, r2=2rr_2 = 2r, lexternal=48l_{external} = 4\sqrt{8}

    48=122(2rr)24\sqrt{8} = \sqrt{12^2 - (2r - r)^2}
    168=144r216 \cdot 8 = 144 - r^2
    128=144r2128 = 144 - r^2
    r2=16r^2 = 16
    r=4r = 4
  5. Conditions for number of common tangent lines

    • Exactly 2 tangent lines: The two circles intersect at two points
    • Exactly 3 tangent lines: The two circles are tangent (internally or externally)
    • Exactly 4 tangent lines: The two circles are separate (do not intersect)