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Functions and Their Modeling

Exponential Function

Understanding Exponential Functions

An exponential function is a mathematical function that has a variable as the exponent of a constant number. The general form of an exponential function is f(x)=abxf(x) = a \cdot b^x with a0a \neq 0, b>0b > 0, and b1b \neq 1.

Components of exponential functions:

In the function f(x)=abxf(x) = a \cdot b^x:

  • aa is the multiplier constant that determines the initial value of the function
  • bb is the exponential base that determines the rate of growth or decay
  • xx is the independent variable (exponent)

Characteristics of Exponential Functions

Exponential functions have several special properties that distinguish them from other functions:

Basic Properties

f(0)=ab0=a1=af(0) = a \cdot b^0 = a \cdot 1 = a
f(x1+x2)=abx1+x2=abx1bx2f(x_1 + x_2) = a \cdot b^{x_1 + x_2} = a \cdot b^{x_1} \cdot b^{x_2}
f(x1x2)=abx1x2=abx1bx2f(x_1 - x_2) = a \cdot b^{x_1 - x_2} = \frac{a \cdot b^{x_1}}{b^{x_2}}

Types of Exponential Functions

Exponential Growth Function (b>1b > 1):

  • Function values increase as xx increases
  • Graph rises from left to right
  • Example: f(x)=2xf(x) = 2^x

Exponential Decay Function (0<b<10 < b < 1):

  • Function values decrease as xx increases
  • Graph falls from left to right
  • Example: f(x)=(0.5)xf(x) = (0.5)^x

Graphs of Exponential Functions

The following is a visualization of various exponential functions:

Comparison of Exponential Functions
The graph shows the growth function f(x)=2xf(x) = 2^x and decay function g(x)=(0.5)xg(x) = (0.5)^x.

Comparison of function values f(x)=2xf(x) = 2^x and g(x)=(0.5)xg(x) = (0.5)^x:

x-2-10123
f(x)=2xf(x) = 2^x0.250.51248
g(x)=(0.5)xg(x) = (0.5)^x4210.50.250.125

Transformations of Exponential Functions

Exponential functions can be transformed in various ways:

Vertical Translation

The function f(x)=abx+cf(x) = a \cdot b^x + c shifts the graph upward (if c>0c > 0) or downward (if c<0c < 0).

Vertical Translation
Comparison of f(x)=2xf(x) = 2^x with g(x)=2x+2g(x) = 2^x + 2.

Horizontal Translation

The function f(x)=abxhf(x) = a \cdot b^{x-h} shifts the graph to the right (if h>0h > 0) or to the left (if h<0h < 0).

Applications of Exponential Functions

Exponential functions are widely used in daily life:

Population Growth

Living organism populations often follow exponential growth patterns. If the initial population is P0P_0 and the growth rate is rr per time period, then:

P(t)=P0(1+r)tP(t) = P_0 \cdot (1 + r)^t

Example: Bacterial population that reproduces every hour at a rate of 20%:

  • Initial population: 1000 bacteria
  • Growth rate: r=0.2r = 0.2
  • Function: P(t)=1000(1.2)tP(t) = 1000 \cdot (1.2)^t

Bacterial Growth Table

Time (hours)012345
Population100012001440172820742488

Radioactive Decay

Radioactive substances decay following exponential functions. If the initial mass is M0M_0 and the half-life is t1/2t_{1/2}, then:

M(t)=M0(12)t/t1/2M(t) = M_0 \cdot \left(\frac{1}{2}\right)^{t/t_{1/2}}

Compound Interest

Investments with compound interest grow exponentially. If the initial capital is PP, interest rate is rr per year, and time is tt years:

A=P(1+rn)ntA = P \cdot \left(1 + \frac{r}{n}\right)^{nt}

where nn is the frequency of interest compounding per year.

Exponential Equations

An exponential equation is an equation that contains a variable in the exponent. General form:

bx=cb^x = c

Method 1: Equalizing Bases

If bf(x)=bg(x)b^{f(x)} = b^{g(x)}, then f(x)=g(x)f(x) = g(x)

Example: Solve 2x+1=82^{x+1} = 8

2x+1=82^{x+1} = 8
2x+1=232^{x+1} = 2^3
x+1=3x + 1 = 3
x=2x = 2

Method 2: Using Logarithms

To solve bx=cb^x = c, use logarithms:

x=logbc=logclogbx = \log_b c = \frac{\log c}{\log b}

Exercises

  1. Determine the value of f(3)f(3) if f(x)=52xf(x) = 5 \cdot 2^x

  2. Solve the equation 32x1=273^{2x-1} = 27

  3. A city's population is 50,000 people and grows 3% per year. What will the population be after 10 years?

  4. A radioactive substance has a half-life of 5 years. If the initial mass is 100 grams, how much mass remains after 15 years?

Answer Key

  1. f(3)=523=58=40f(3) = 5 \cdot 2^3 = 5 \cdot 8 = 40
  2. 32x1=27=333^{2x-1} = 27 = 3^3, so 2x1=32x - 1 = 3 , therefore x=2x = 2

  3. P(10)=50000(1.03)10=500001.344=67.195P(10) = 50000 \cdot (1.03)^{10} = 50000 \cdot 1.344 = 67.195 people

  4. M(15)=100(12)15/5=100(12)3=10018=12.5M(15) = 100 \cdot \left(\frac{1}{2}\right)^{15/5} = 100 \cdot \left(\frac{1}{2}\right)^3 = 100 \cdot \frac{1}{8} = 12.5 grams