• Nakafa

    Nakafa

    Learn free and with quality.
Subject
    • Grade 10
    • Grade 11
    • Grade 12
Exercises
Holy
  • Quran
Articles
  • Politics
  • Community
  • About

Command Palette

Search for a command to run...

Geometric Transformation

Reflection over Line y = h

Understanding Reflection over the Line y = h

Reflection over the horizontal line y=hy = hy=h is a geometric transformation that maps each point of an object to a new position. The line y=hy = hy=h acts as a mirror.

The vertical distance from the original point to the mirror line is equal to the vertical distance from the image point to the mirror line. The x-coordinate of the point does not change.

Rule for Reflection over the Line y = h

If a point P(x,y)P(x, y)P(x,y) is reflected over the line y=hy = hy=h, its image's coordinates, P′(x′,y′)P'(x', y')P′(x′,y′), are determined by the rule:

x′=xx' = xx′=x
y′=2h−yy' = 2h - yy′=2h−y

Thus, the image of point P(x,y)P(x, y)P(x,y) is P′(x,2h−y)P'(x, 2h - y)P′(x,2h−y). Note that the x-coordinate remains the same, while the y-coordinate changes based on its distance from the line y=hy=hy=h.

Reflecting a Point over the Line y = h

Determine the image of point P(3,2)P(3,2)P(3,2) by reflection over the line y=3y=3y=3.

In this case, x=3x=3x=3, y=2y=2y=2, and h=3h=3h=3.

Using the rule P′(x,2h−y)P'(x, 2h - y)P′(x,2h−y):

x′=3x' = 3x′=3
y′=2(3)−2=6−2=4y' = 2(3) - 2 = 6 - 2 = 4y′=2(3)−2=6−2=4

Thus, the image of point P(3,2)P(3,2)P(3,2) is P′(3,4)P'(3,4)P′(3,4).

Now, let's visualize this example.

Image of Point P(3,2)P(3,2)P(3,2) over Line y=3y=3y=3
Visualization of the reflection of point P(3,2)P(3,2)P(3,2) over the line y=3y=3y=3 resulting in P′(3,4)P'(3,4)P′(3,4).

Exercises

  1. Determine the image of point P(5,−4)P(5,-4)P(5,−4) by reflection over the line y=−2y=-2y=−2.
  2. A point Q(−1,−3)Q(-1, -3)Q(−1,−3) is reflected over the line y=0y=0y=0 (X-axis). Determine the coordinates of its image!
  3. The image of a point R(x,y)R(x,y)R(x,y) after reflection over the line y=4y=4y=4 is R′(−2,5)R'(-2,5)R′(−2,5). Determine the coordinates of point R!

Key Answers

  1. Given P(5,−4)P(5,-4)P(5,−4) and the mirror line y=−2y=-2y=−2. So x=5,y=−4,h=−2x=5, y=-4, h=-2x=5,y=−4,h=−2.

    x′=x=5x' = x = 5x′=x=5
    y′=2h−y=2(−2)−(−4)=−4+4=0y' = 2h - y = 2(-2) - (-4) = -4 + 4 = 0y′=2h−y=2(−2)−(−4)=−4+4=0

    Thus, the image of point P is P′(5,0)P'(5,0)P′(5,0).

  2. Given Q(−1,−3)Q(-1, -3)Q(−1,−3) and the mirror line y=0y=0y=0. So x=−1,y=−3,h=0x=-1, y=-3, h=0x=−1,y=−3,h=0.

    x′=x=−1x' = x = -1x′=x=−1
    y′=2h−y=2(0)−(−3)=0+3=3y' = 2h - y = 2(0) - (-3) = 0 + 3 = 3y′=2h−y=2(0)−(−3)=0+3=3

    Thus, the image of point Q is Q′(−1,3)Q'(-1,3)Q′(−1,3).

  3. Given the image R′(−2,5)R'(-2,5)R′(−2,5) and the mirror line y=4y=4y=4. So x′=−2,y′=5,h=4x'=-2, y'=5, h=4x′=−2,y′=5,h=4.

    We know x′=xx' = xx′=x and y′=2h−yy' = 2h - yy′=2h−y.

    From x′=xx' = xx′=x, then x=−2x = -2x=−2.

    From y′=2h−yy' = 2h - yy′=2h−y, then 5=2(4)−y5 = 2(4) - y5=2(4)−y.

    5=8−y5 = 8 - y5=8−y
    y=8−5y = 8 - 5y=8−5
    y=3y = 3y=3

    Thus, the coordinates of point R are R(−2,3)R(-2,3)R(−2,3).

Previous

Reflection over Line x = k

Next

Reflection over Point

  • Reflection over Line y = hUnderstand horizontal line reflections y = h with worked examples and visual guides. Apply the P'(x, 2h-y) formula to solve geometry problems.
On this page
  • Understanding Reflection over the Line y = h
    • Rule for Reflection over the Line y = h
  • Reflecting a Point over the Line y = h
  • Exercises
    • Key Answers
  • Comments
  • Report
  • Source code