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Understanding Parabola

Have you ever thrown a basketball to the hoop? Or seen a water fountain spraying water into the air? The trajectory formed by these movements creates a very special curve in mathematics, called a parabola.

A parabola is not just an ordinary curve. Its unique shape makes it very useful in real life. Satellite antennas are parabolic in shape to capture signals, spotlights use parabolic reflectors to focus light, and even bridges and modern architecture often use parabolic arches for their strength.

What's interesting about parabolas is their perfect reflection property. All rays that come parallel to the parabola's axis will be reflected toward one point called the focus. This is why parabolas are so effective for collecting or transmitting energy.

Parabola y=ax2y = ax^2 in Real Life
Visualization of parabola with focus at F(0,14a)F(0, \frac{1}{4a}) and directrix y=14ay = -\frac{1}{4a}.

Mathematical Definition

Mathematically, a parabola is the locus of points that are equidistant from a fixed point and a fixed line. The fixed point is called the focus, while the fixed line is called the directrix.

Imagine you have one point (focus) and one straight line (directrix). Now find all points whose distance to the focus equals their distance to the directrix. The collection of these points is what forms a parabola!

This definition gives us a systematic way to understand parabolas. No matter what the orientation or position, as long as it satisfies the condition of equal distance to the focus and directrix, then it is a parabola.

This unique property of parabolas makes every point on the curve have a perfect "balance" of distance between the focus and directrix.

Standard Parabola Equations

Let's start with the simplest parabola: a parabola with vertex at the origin O(0,0)O(0,0). There are four basic standard parabola forms depending on the direction of the curve's opening.

Four Standard Parabola Forms with Vertex O(0,0)O(0,0)
Standard parabolas x2=4pyx^2 = 4py (vertical) and y2=4pxy^2 = 4px (horizontal).

The four standard parabola equation forms are:

y2=4px(opens rightward)y^2 = 4px \quad \text{(opens rightward)}
y2=4px(opens leftward)y^2 = -4px \quad \text{(opens leftward)}
x2=4py(opens upward)x^2 = 4py \quad \text{(opens upward)}
x2=4py(opens downward)x^2 = -4py \quad \text{(opens downward)}

The value pp in these equations represents the distance from vertex to focus. The larger the value of pp, the more "open" the parabola becomes.

For example, for the parabola y2=4pxy^2 = 4px (opens rightward):

Vertex: (0,0)\text{Vertex: } (0, 0)
Focus: (p,0)\text{Focus: } (p, 0)
Directrix: x=p\text{Directrix: } x = -p
Axis of symmetry: X-axis\text{Axis of symmetry: } X\text{-axis}

Remember that the sign of pp determines the opening direction: positive for right/up, negative for left/down.

Parabola with Arbitrary Vertex

In real applications, parabolas don't always center at the origin. A parabola can have its vertex at any point (h,k)(h, k). This is the general form of parabola.

Parabola (xh)2=4p(yk)(x-h)^2 = 4p(y-k) with Vertex (h,k)(h,k)
Parabola with vertex at (2,1)(2, 1) and parameter p=0.5p = 0.5.

General form of parabola equations with vertex at (h,k)(h, k):

(yk)2=4p(xh)(horizontal)(y-k)^2 = 4p(x-h) \quad \text{(horizontal)}
(xh)2=4p(yk)(vertical)(x-h)^2 = 4p(y-k) \quad \text{(vertical)}

For vertical parabola (xh)2=4p(yk)(x-h)^2 = 4p(y-k):

Vertex: (h,k)\text{Vertex: } (h, k)
Focus: (h,k+p)\text{Focus: } (h, k+p)
Directrix: y=kp\text{Directrix: } y = k-p
Axis of symmetry: x=h\text{Axis of symmetry: } x = h

For horizontal parabola (yk)2=4p(xh)(y-k)^2 = 4p(x-h):

Vertex: (h,k)\text{Vertex: } (h, k)
Focus: (h+p,k)\text{Focus: } (h+p, k)
Directrix: x=hp\text{Directrix: } x = h-p
Axis of symmetry: y=k\text{Axis of symmetry: } y = k

The sign of pp determines the parabola's opening direction. Positive for up/right, negative for down/left.

Determining Parabola Elements

When given a parabola equation, we can identify all its important elements systematically. The first step is to recognize the parabola's orientation:

  • If variable xx is squared → vertical parabola (opens up/down)
  • If variable yy is squared → horizontal parabola (opens left/right)

Let's see how to do this with an example.

Example: Given a parabola with equation x24x8y+12=0x^2 - 4x - 8y + 12 = 0

The first step is to convert to standard form by completing the square:

x24x8y+12=0x^2 - 4x - 8y + 12 = 0
x24x=8y12x^2 - 4x = 8y - 12
x24x+4=8y12+4x^2 - 4x + 4 = 8y - 12 + 4
(x2)2=8y8(x-2)^2 = 8y - 8
(x2)2=8(y1)(x-2)^2 = 8(y-1)

From the form (x2)2=8(y1)(x-2)^2 = 8(y-1), we identify:

  • h=2h = 2, k=1k = 1
  • 4p=84p = 8, so p=2p = 2

Therefore, the parabola elements are:

Parabola Analysis (x2)2=8(y1)(x-2)^2 = 8(y-1)
Identifying vertex (2,1)(2,1), focus (2,3)(2,3), directrix y=1y = -1, and p=2p = 2.

From this analysis we obtain:

Vertex: (2,1)\text{Vertex: } (2, 1)
Focus: (2,3)\text{Focus: } (2, 3)
Directrix: y=1\text{Directrix: } y = -1
Axis of symmetry: x=2\text{Axis of symmetry: } x = 2
Opening direction: upward (since p=2>0)\text{Opening direction: upward (since } p = 2 > 0\text{)}

Example Problems

Let's work through some problems to deepen our understanding of parabolas.

Problem 1: Determine the equation of a parabola that has vertex at (1,2)(1, -2) and focus at (4,2)(4, -2).

Solution:

Since the vertex and focus have the same y-coordinate, this parabola is horizontal.

Vertex: (h,k)=(1,2)\text{Vertex: } (h, k) = (1, -2)
Focus: (h+p,k)=(4,2)\text{Focus: } (h+p, k) = (4, -2)

From the focus condition, we get h+p=4h + p = 4. Substituting h=1h = 1:

1+p=4p=31 + p = 4 \Rightarrow p = 3

The equation for a horizontal parabola is (yk)2=4p(xh)(y-k)^2 = 4p(x-h):

(y(2))2=4(3)(x1)(y-(-2))^2 = 4(3)(x-1)
(y+2)2=12(x1)(y+2)^2 = 12(x-1)

Problem 2: For parabola y26y4x+13=0y^2 - 6y - 4x + 13 = 0. Determine the coordinates of the vertex and focus.

Solution:

Complete the square for variable yy:

y26y4x+13=0y^2 - 6y - 4x + 13 = 0
y26y=4x13y^2 - 6y = 4x - 13
y26y+9=4x13+9y^2 - 6y + 9 = 4x - 13 + 9
(y3)2=4x4(y-3)^2 = 4x - 4
(y3)2=4(x1)(y-3)^2 = 4(x-1)

From the form (y3)2=4(x1)(y-3)^2 = 4(x-1), we identify:

h=1,k=3h = 1, \quad k = 3
4p=4p=14p = 4 \Rightarrow p = 1

Therefore:

Vertex: (h,k)=(1,3)\text{Vertex: } (h, k) = (1, 3)
Focus: (h+p,k)=(1+1,3)=(2,3)\text{Focus: } (h+p, k) = (1+1, 3) = (2, 3)