Rearranging Complex Expressions without Changing Their Value
Addition and scalar multiplication of complex numbers obey the same familiar algebraic rules as real numbers. Under those rules, expressions can be rearranged and simplified without changing their value.
Let , , and be any complex numbers, and let and be any scalars (real numbers).
Addition Properties
Addition of complex numbers keeps the familiar properties of real addition, and each check runs on the real part and the imaginary part separately. Splitting a sum into two real sums is what keeps those proofs short.
Commutativity
Changing the order of two complex addends does not change their sum.
Example:
Addition Associativity
When adding three complex numbers, the grouping of the addition does not affect the result.
Identity Element
There exists a complex number (zero) such that when added to any complex number , the result is itself.
Inverse Element
Every complex number has an additive inverse (opposite), denoted by , such that their sum is the zero element ().
Example:
If , then .
Then .
Scalar Multiplication
Multiplying by a real scalar follows the same group of properties, so the same checks apply with one real factor. The scalar touches the real part and the imaginary part in the same way, which is why distributivity and the zero scalar keep working.
Multiplication Associativity
The grouping of scalar multiplication does not affect the result.
Scalar Distributivity
Multiplying a complex number by a sum of scalars is equivalent to multiplying it by each scalar and then adding the results.
Complex Distributivity
A scalar can be distributed over the addition of complex numbers.
Scalar Identity
Multiplying a complex number by the scalar does not change the complex number.
Zero Scalar
Multiplying a complex number by the scalar results in the complex number zero.
Simplifying Expressions with Addition Properties
Distributivity carries a scalar into a sum term by term, and equal coefficients with opposite signs then cancel. Both moves keep the real part and the imaginary part unchanged, so any identity built from them holds for every complex number.
Verifying the Additive Inverse
Show that for any complex number , holds.
Solution:
Use distributivity to combine the scalar coefficients, then use the fact that multiplying by the zero scalar gives zero.
Apply the distributive property:
Multiplication by the zero scalar gives:
It is proven that .
Exercise
Using the addition properties, prove that for any complex number . Work on the left side only, and name the property you apply at each step, so the argument covers every complex number.
Worked Solution
Write subtraction as addition of the opposite:
Regroup the scalar factors:
Multiply the scalars:
Apply the distributive property:
It is proven that .