Properties of the Modulus of a Complex Number

Modulus Under Negation and Conjugation

Negation and conjugation leave the modulus of a complex number unchanged.

Explanation:

Recall that if $z_1 = x + iy$, then $-z_1 = -x - iy$ and $\bar{z_1} = x - iy$.

• $|z_1| = \sqrt{x^2 + y^2}$
• $|-z_1| = \sqrt{(-x)^2 + (-y)^2} = \sqrt{x^2 + y^2}$
• $|\bar{z_1}| = \sqrt{x^2 + (-y)^2} = \sqrt{x^2 + y^2}$

All three yield the same value.

Modulus of Difference

The modulus of the difference of two complex numbers is the same if the order is reversed.

Explanation:

This is a direct consequence of the first property. We know $z_1 - z_2 = -(z_2 - z_1)$. Then:

Square of Modulus

The square of the modulus of a complex number is equal to the complex number multiplied by its conjugate.

Explanation:

If $z_1 = x + iy$, then $\bar{z_1} = x - iy$.

We also know that $|z_1| = \sqrt{x^2 + y^2}$, so $|z_1|^2 = (\sqrt{x^2 + y^2})^2 = x^2 + y^2$.

Both sides are equal.

Modulus of Product

The modulus of the product of two complex numbers is equal to the product of their individual moduli.

This follows from multiplying each number by its conjugate:

Both moduli are non-negative, so taking the square root gives the product rule.

Modulus of Quotient

The modulus of the quotient of two complex numbers is equal to the quotient of their individual moduli (provided the denominator is non-zero).

The quotient rule follows from the product rule because $z_1=(z_1/z_2)z_2$ when $z_2\neq0$.

Triangle Inequality

The modulus of the sum of two complex numbers is less than or equal to the sum of their individual moduli.

Explanation:

Geometrically, place the vectors $z_1$ and $z_2$ head to tail. The direct vector from the starting point to the endpoint is $z_1 + z_2$, and its length cannot exceed the sum $|z_1| + |z_2|$ of the other two side lengths.

Reverse Triangle Inequality

The difference between the moduli of two complex numbers cannot exceed the distance between the numbers themselves.

This inequality provides a lower bound for a distance or sum. For example, replacing $z_2$ with $-z_2$ gives $\bigl||z_1|-|z_2|\bigr| \leq |z_1+z_2|$.

Using Modulus Properties

Suppose we are given the complex number $z = \frac{1 - 2i}{3 + 4i}$. Find $|z|$.

Solution:

We can view $z = \frac{z_1}{z_2}$ with $z_1 = 1 - 2i$ and $z_2 = 3 + 4i$.

Using the Modulus of Quotient property:

Now we calculate the moduli of $z_1$ and $z_2$:

The calculation gives:

The quotient rule avoids expanding the fraction with the conjugate of the denominator before calculating its modulus.

Exercise

1. If $z_1 = 6 + 8i$ and $z_2 = 3 - i$, calculate $|z_1 \times z_2|$ using the modulus properties.
2. If $z = 5 - 12i$, prove that $|z|^2 = z \times \bar{z}$.
3. If $|z_1|=3$ and $|z_2|=5$, determine the possible bounds for $|z_1+z_2|$.

Worked Solutions

1. We use the property $|z_1 \times z_2| = |z_1| \times |z_2|$.

   Calculate each modulus:

   $$|z_1| = |6 + 8i| = \sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10$$

   Then:

   $$|z_1 \times z_2| = |z_1| \times |z_2| = 10 \times \sqrt{10} = 10\sqrt{10}$$

2. Given $z = 5 - 12i$.

   Calculate the left side ($|z|^2$):

   $$|z| = |5 - 12i| = \sqrt{5^2 + (-12)^2} = \sqrt{25 + 144} = \sqrt{169} = 13$$

3. The ordinary and reverse triangle inequalities give an upper and a lower bound:

   $$\bigl||z_1|-|z_2|\bigr|\leq|z_1+z_2|\leq|z_1|+|z_2|$$

Published: May 1, 2025. Updated: Sep 1, 2026.

Calculate the right side ($z \times \bar{z}$):

The conjugate of $z$ is $\bar{z} = 5 + 12i$.

Since the left side ($169$) equals the right side ($169$), the statement $|z|^2 = z \times \bar{z}$ is proven.

Substituting the known moduli gives $2\leq|z_1+z_2|\leq8$. The exact value depends on the angle between the two complex numbers.