In the Riemann Sums material, we learned how to approximate the area under a curve by dividing it into many rectangles. We also know that the more rectangles we use (the larger the value of n), the more accurate our area approximation becomes.
Now, imagine if we could divide the area into an infinite number of rectangles. The width of each rectangle (Δx) would become infinitesimally small, approaching zero. This process of taking the limit as the number of partitions n approaches infinity is what transforms the Riemann Sum from a mere approximation into an exact calculation. This very concept gives rise to the .
The definite integral is the formal way of writing this "infinite sum" of the areas of infinitesimally small rectangles. Mathematically, the definite integral is defined as the limit of a Riemann Sum.
∫abf(x)dx=n→∞limi=1∑nf(xi)Δx
This notation has a specific meaning:
∫ab: This is the integral symbol with a lower limit a and an upper limit b. These numbers define the interval over which we are calculating the area.
f(x): This is the integrand, which is the function whose curve we are finding the area under.
dx: Just as with indefinite integrals, this indicates that we are integrating with respect to the variable x.
Unlike an indefinite integral, which results in a function (F(x)+C), the result of a definite integral is a single number that represents the net area under the curve from x=a to x=b.
Let's try to calculate the exact value of a definite integral using its limit definition, as in the reference example.
Problem: Determine the value of ∫07xdx.
Solution:
To solve this, we will convert it back to the limit form of a Riemann Sum.
Step1: Determine the Riemann Sum components
From the problem ∫07xdx, we know:
Function: f(x)=x
Interval: [a,b]=[0,7]
Thus, the width of each subinterval is:
Δx=nb−a=n7−0=n7
We will use the right endpoint (xi) as the sample point for each partition:
xi=a+iΔx=0+i(n7)=n7i
Step2: Set up the Riemann Sum
The height of each rectangle is f(xi), so:
f(xi)=xi=n7i
Now, we plug this into the Riemann Sum formula:
i=1∑nf(xi)Δx=i=1∑n(n7i)(n7)=i=1∑nn249i
Step3: Simplify and use summation properties
We can factor constants out of the sigma notation, as n is treated as a constant in the sum from i=1 to n.
n249i=1∑ni
Next, we replace ∑i=1ni with its series summation formula, 2n(n+1), and then simplify the expression to make it easier to evaluate the limit.
n249⋅2n(n+1)
=2n249n(n+1)
=2n49(n+1)
=249(nn+1)=249(1+n1)
The simplification steps above ensure we get the easiest form to evaluate the limit. First, we cancel n from the numerator and denominator, then we split the fraction.
To solve the limit of a Riemann Sum, we often need some common series summation formulas:
∑i=1ni=2n(n+1)
∑i=1ni2=6n(n+1)(2n+1)
∑i=1ni3=(2n(n+1))2
Step4: Take the Limit
Finally, we take the limit as n→∞ to find the exact area.
∫07xdx=n→∞lim249(1+n1)
=249(1+0)
=249
So, the exact area of the region under the curve f(x)=x from x=0 to x=7 is 249 or 24.5. This is an example of how the definite integral provides an exact answer, no longer an approximation.
