0000:00:00:00:00Mulai17Nomor 17PembahasanDiberikan fungsi f(x)=(x+3)(x2+6x+8)4f(x) = (x+3)(x^2+6x+8)^4f(x)=(x+3)(x2+6x+8)4 dan F(x)=∫f(x) dxF(x) = \int f(x) \, dxF(x)=∫f(x)dx. Jika F(−3)=2F(-3) = 2F(−3)=2, maka fungsi F(x)F(x)F(x) adalah ....110(x2+6x+8)5+110\frac{1}{10}(x^2+6x+8)^5 + \frac{1}{10}101(x2+6x+8)5+101110(x2+6x+8)5+1110\frac{1}{10}(x^2+6x+8)^5 + \frac{11}{10}101(x2+6x+8)5+1011110(x2+6x+8)5+2110\frac{1}{10}(x^2+6x+8)^5 + \frac{21}{10}101(x2+6x+8)5+1021110(x2+6x+8)5+3110\frac{1}{10}(x^2+6x+8)^5 + \frac{31}{10}101(x2+6x+8)5+1031110(x2+6x+8)5+4110\frac{1}{10}(x^2+6x+8)^5 + \frac{41}{10}101(x2+6x+8)5+1041
17Nomor 17PembahasanDiberikan fungsi f(x)=(x+3)(x2+6x+8)4f(x) = (x+3)(x^2+6x+8)^4f(x)=(x+3)(x2+6x+8)4 dan F(x)=∫f(x) dxF(x) = \int f(x) \, dxF(x)=∫f(x)dx. Jika F(−3)=2F(-3) = 2F(−3)=2, maka fungsi F(x)F(x)F(x) adalah ....110(x2+6x+8)5+110\frac{1}{10}(x^2+6x+8)^5 + \frac{1}{10}101(x2+6x+8)5+101110(x2+6x+8)5+1110\frac{1}{10}(x^2+6x+8)^5 + \frac{11}{10}101(x2+6x+8)5+1011110(x2+6x+8)5+2110\frac{1}{10}(x^2+6x+8)^5 + \frac{21}{10}101(x2+6x+8)5+1021110(x2+6x+8)5+3110\frac{1}{10}(x^2+6x+8)^5 + \frac{31}{10}101(x2+6x+8)5+1031110(x2+6x+8)5+4110\frac{1}{10}(x^2+6x+8)^5 + \frac{41}{10}101(x2+6x+8)5+1041
