Problem 7 - Set 2 - Try Out - General Reasoning - SNBT

A password consists of $4$ characters consisting of digits and vowels with the following order:

DIGIT	LETTER	DIGIT	LETTER

The rules for arrangement are:

Determine how many password arrangements can be formed from these rules?

We will determine the number of password arrangements based on the position rules shown in the following table:

Even Digit	First Letter (Not E)	Digit from $\{5, 6, 7\}$	Second Letter (U)
$2, 4, 6, 8$	A, I, U, O	$5, 6, 7$	U
$4$	$4$	$3$	$1$

From the table above, we get the number of choices for each position:

Since each position must be filled simultaneously, we use the multiplication rule:

4 \times 4 \times 3 \times 1 = 48

Thus, there are $48$ possible password arrangements.

Command Palette