Given functions f(x)=2x−3 and (g∘f)(x)=4x2−12x+10. The value of g(1) is ....
Explanation
We are given the function f(x)=2x−3 and the composite function (g∘f)(x)=4x2−12x+10. We are asked to find the value of g(1).
The definition of a composite function is (g∘f)(x)=g(f(x)). Let u=f(x)=2x−3. We rearrange this equation to express x in terms of u:
2x=u+3
x=2u+3
Substitute x into the equation (g∘f)(x):
g(u)=4(2u+3)2−12(2u+3)+10
g(u)=4(4u2+6u+9)−6(u+3)+10
g(u)=(u2+6u+9)−(6u+18)+10
g(u)=u2+6u−6u+9−18+10
g(u)=u2+1
Thus, we have g(x)=x2+1.
Then the value of g(1) is:
g(1)=12+1=1+1=2
So, the value of g(1) is 2.