The value of x that satisfies 3x2xx=3112 is ....
Explanation
We are given the following determinant equation:
3x2xx=3112
The first step is to calculate the determinant of the matrices on the left and right sides. Recall that the determinant of a matrix (acbd) is ad−bc.
Determinant of the left side:
3x2xx=(3x)(x)−(x)(2)=3x2−2x
Determinant of the right side:
3112=(3)(2)−(1)(1)=6−1=5
Now we equate both results:
3x2−2x=5
Move 5 to the left side to form a quadratic equation:
3x2−2x−5=0
We factor this quadratic equation. We look for two numbers that multiply to 3×(−5)=−15 and sum to −2. These numbers are −5 and 3.
3x2−5x+3x−5=0
x(3x−5)+1(3x−5)=0
(x+1)(3x−5)=0
Thus, the solutions are:
x+1=0⇒x=−1
3x−5=0⇒x=35
So, the values of x that satisfy the equation are 35 and −1.