If W(P@Q#R)=2P2−Q+3R, then the value of W(5@8#4)= ....
Explanation
Given the function operation definition W(P@Q#R)=2P2−Q+3R.
We are asked to find the value of W(5@8#4).
Based on the position of variables in the function definition, we can identify the following values:
- P=5
- Q=8
- R=4
Substitute these values into the function equation:
W(5@8#4)=2(5)2−8+34
Perform the calculation step by step:
- Calculate the square: 52=25
- Calculate the square root: 4=2
Then the equation becomes:
W(5@8#4)=2(25)−8+3(2)
W(5@8#4)=50−8+6
W(5@8#4)=42+6
W(5@8#4)=48
So, the value of W(5@8#4) is 48.