Question 33

Explanation

To solve $\int (2\sin 2x - 3\cos x) dx$, integrate each term separately

Separating the Integral

Integrating Each Term

For $\int \sin 2x \, dx$, use substitution $u = 2x$

For $\int \cos x \, dx$

Combining Results

Therefore, the result of $\int (2\sin 2x - 3\cos x) dx = -\cos 2x - 3\sin x + C$