For diagonal matrices, eigenvalues can be read directly from their main diagonal entries. This is one of the most fascinating features in linear algebra.
The eigenvalues of a square diagonal matrix or triangular matrix A∈Kn×n
A=a110⋱0ann
or A=a110∗⋱ann
or A=a11∗⋱0ann
are its main diagonal entries:
λ1=a11,…,λn=ann
Why is this true? Since χA(t)=det(A−t⋅I)=(a11−t)⋯(ann−t) with roots a11,…,ann.
This property greatly simplifies our work because we don't need to calculate determinants or solve complex characteristic equations.
Triangular matrices have the same property as diagonal matrices. For both upper and lower triangular matrices, the eigenvalues are still the main diagonal entries.
This happens because when we calculate det(A−tI), the entries above or below the main diagonal don't affect the determinant calculation. The triangular structure allows the determinant to be computed as the product of diagonal entries.
There's a fundamental relationship between eigenvalues and the determinant and trace of a matrix. If the characteristic polynomial χA(t) can be factored linearly in K, which means matrix A has n eigenvalues λ1,…,λn∈K, then:
detA=i=1∏nλi
trA=i=1∑nλi
The determinant is the product of all eigenvalues, and the trace is the sum of all eigenvalues.
Let's verify with our previous examples:
For A=(11−11) with λ1=1+i, λ2=1−i:
detA=1⋅1−1⋅(−1)=2=λ1⋅λ2
trA=1+1=2=λ1+λ2
For A=(1i−i1) with λ1=2, λ2=0:
detA=1⋅1−i⋅(−i)=0=λ1⋅λ2
trA=1+1=2=λ1+λ2
This relationship is very useful for verifying calculations and provides geometric insights into the linear transformation represented by the matrix.