The sequence of real numbers a1,a2,a3,… satisfies an+1=4an+1 for natural number n and a4=85. The number that divides a2025−a2024 is ....
Explanation
We are asked to find a number that divides the difference between two consecutive terms, a2025−a2024.
To make it easier, let's find the pattern of the difference between consecutive terms by calculating the initial terms first.
We know a4=85 and the formula an+1=4an+1. We can find the previous term by reversing the formula:
Finding the values of initial terms
-
Find a3:
a3=4a4−1=485−1=484=21 -
Find a2:
a2=4a3−1=421−1=420=5 -
Find a1:
a1=4a2−1=45−1=44=1
Observing the pattern of differences between terms
Let's calculate the difference between adjacent terms:
- a2−a1=5−1=4=41
- a3−a2=21−5=16=42
- a4−a3=85−21=64=43
From the pattern above, we can see that the difference between the (n+1)-th and n-th term is a power of 4:
Determining the divisor
Based on the pattern we found, the difference a2025−a2024 is:
The value 42024 is a power of 4. Therefore, this number is definitely divisible by 4.
Thus, the number that divides a2025−a2024 is 4.